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Semmy [17]
3 years ago
7

Given f(x)= x square+ 6x + 12 show that f(x) ≥3 for al values of x the answer plz faaassst

Mathematics
1 answer:
nignag [31]3 years ago
6 0

Step-by-step explanation:

f(x) = x² + 6x + 12

= (x² + 6x + 9) + 3

= (x + 3)² + 3.

Since a² >= 0 for all real values of a,

(x + 3)² >= 0 for all real values of x,

(x + 3)² + 3 >= 3 for all real values of x.

Hence f(x) >= 3. (Shown)

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a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

<h3>How to find the cost of each call ?</h3>

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

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a. to find the cost of a call for six minutes.

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Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

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c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6)  \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62

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c.to find the cost of a 9 ½2-minute call

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c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9  \frac{1}{2} 2) = 1.66

Therefore,the cost of a 9 ½2-minute call is 1.66.

Learn more about problems on cost of call, refer:

brainly.com/question/16584226

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