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Artemon [7]
3 years ago
8

Rate of 33.00 for 11 pounds of meat

Mathematics
2 answers:
gtnhenbr [62]3 years ago
4 0
The answer is 3

hope this helps :)
Inga [223]3 years ago
3 0
It would be 3 because if u divide that the answer would be 3

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Ierofanga [76]

Answer:

hello dude you see um this is complicated

Step-by-step explanation:

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2 years ago
A news report states that the 99% confidence interval for the mean number of daily calories consumed by participants in a medica
expeople1 [14]

Answer:

The sample mean is of 1925 calories.

The margin of error is of 75 calories.

The sample standard deviation is of 109.7992 calories.

Step-by-step explanation:

Sample mean:

The sample mean is the mean value of the two bounds of the confidence interval. So

M = \frac{1850 + 2000}{2} = 1925

The sample mean is of 1925 calories.

The margin of error

Difference between the bounds and the sample mean. So

2000 - 1925 = 1925 - 1850 = 75 calories.

The margin of error is of 75 calories.

Sample standard deviation:

Here, I am going to expand on the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 18 - 1 = 17

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 17 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.898

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample.

Since M = 75, T = 2.898, n = 18

M = T\frac{s}{\sqrt{n}}

75 = 2.898\frac{s}{\sqrt{18}}

s = \frac{75\sqrt{18}}{2.898}

s = 109.7992

The sample standard deviation is of 109.7992 calories.

6 0
2 years ago
Congruent Triangles and Proofs<br><br> Given: JK bisects
Nikitich [7]

Answer:

Step-by-step explanation:

1S. JM bisects ∠ KJL and  ∠JMK ≅ ∠JML

1R. Given

2S. ∠KJM ≅ ∠LJM

2R. Angle bisectors form ≅ ∠s

3S. JM≅JM

3R. Reflexive Propriety ( segment is ≅ with itself)

4S. ΔJMK ≅ΔJML

4R. ASA theorem of congruency

5S. JK≅JL

5R. Coresponding parts of congruent Δs are congruent (CPCTC)

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3 years ago
What is the solution to log2(2x°-8)– 2log2x = log2x?
Butoxors [25]
Ima be honest I don’t know this one
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3 years ago
Emily needs to buy 4 notebooks each notebook cost .60 how much will she pay in total
Dmitry [639]

Answer: $2.40

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3 years ago
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