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OleMash [197]
2 years ago
12

What is the image of ( − 5 , 4 ) (−5,4) after a reflection over the line y = x y=x?

Mathematics
1 answer:
balandron [24]2 years ago
7 0

Answer:

(4,−5)

Step-by-step explanation:

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What is the area of the base of a triangular prism if the volume is 210 ft3 and the height is 14 ft?
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We have the area of the base of a triangular prism= a*b
the volume of triangular prism =a*b*c( where c is the height) so that 210=a*b*14 ==> 210= base area*14==> base area= 210/14
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V
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Answer:5

Step-by-step explanation:

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Which names are correct for FM−→− ?
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Answer with explanation:

⇒A segment , \Bar {AB} is equivalent to \Bar {BA}.

⇒We can assert this by this way, if Distance between Two points A and B is 6 unit, then Distance between B and A will be 6 unit also.

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\bar{FM}=\bar{MF}

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Option A

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Find the quotient of 21x^2y^6+6xy^3-30xy/3xy.
kaheart [24]
\bf ~~~~~~~~~~~~\textit{negative exponents}
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a^{-n} \implies \cfrac{1}{a^n}
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-------------------------------

\bf \cfrac{21x^2y^6+6xy^3-30xy}{3xy}\implies \stackrel{\textit{distributing the denominator}}{\cfrac{21x^2y^6}{3xy}+\cfrac{6xy^3}{3xy}-\cfrac{30xy}{3xy}}
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\cfrac{21}{3}\cdot x^2x^{-1}y^6y^{-1}+\cfrac{6}{3}\cdot x^1x^{-1}y^3y^{-1}-\cfrac{30}{3}\cdot x^1x^{-1}y^1y^{-1}
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7x^{2-1}y^{6-1}+2x^{1-1}y^{3-1}-10x^{1-1}y^{1-1}\implies 7xy^5+2y^2-10
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Verify:<br>cos(2A)=(cotA-tanA)/cscAsecA​
kolbaska11 [484]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

cot A = \frac{cosA}{sinA}, tanA = \frac{sinA}{cosA}, cscA  = \frac{1}{sinA}, secA = \frac{1}{cosA}

Consider the right side

\frac{cotA-tanA}{cscAsecA}

= \frac{\frac{cosA}{sinA}-\frac{sinA}{cosA}  }{\frac{1}{sinA}.\frac{1}{cosA}  }

= \frac{\frac{cos^2A-sin^2A}{sinAcosA} }{\frac{1}{sinAcosA} }

= \frac{cos^2A-sin^2A}{sinAcosA} × sinAcosA ( cancel sinAcosA )

= cos²A - sin²A

= cos2A

= left side ⇒ verified

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3 years ago
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