Answer:
7/9
Step-by-step explanation:
Answer:
4 inches
Step-by-step explanation:
40/24=10/6
40/10=4
24/6=4
(40/24)/(4/4)=10/6
(10/6)(4/4)=10/24
Answer:
B)
Step-by-step explanation:
In statistics, an outlier is a data point that differs significantly from other observations.
This can happen because of different reasons: it may be due to variability in the measurement or it may indicate an actual experimental error. If it is an actual experimental error then it can create problems when doing the statistical analysis.
A) We can say that this is true, the outliers are observed values far from the other data, however we can make a much deeper analysis of this.
B) This is the right answer, since we don't know what is really causing the outlier, we need to take a closer look to see if they are just mistakes (and therefore be removed). If they are not mistakes we need to do the analysis with and without them to reach correct conclusions.
C) this is wrong because although the part of the histogram is true. It is not true that they should be ignored.
d) The outliers differ significantly from the other data but this doesn't make them the minimum and maximum values in a data set and therefore they should not be treated as such.
Therefore, the correct answer is B)
Each pound of squash cost $0.49 while each pound of eggplant cost $0.69.
Let x represent the cost of each pound of squash and y represent the cost of each pound of eggplant.
3 pounds of squash and 2 pounds of eggplants cost $2.85. Hence:
3x + 2y = 2.85 (1)
4 pounds of squash and 5 pounds of eggplants cost $5.41. Hence:
4x + 5y = 5.41 (2)
Solving equation 1 and 2 simultaneously gives:
x = 0.49, y = 0.69
Each pound of squash cost $0.49 while each pound of eggplant cost $0.69.
Find out more at: brainly.com/question/21105092
Answer:
Step-by-step explanation:
Given
See attachment
From the attachment, we have:
First, we need to calculate length LM,
Using Pythagoras theorem:
Collect Like Terms
Solving (a): 
Substitute values for MN and LN
Solving (b): 
Substitute values for LM and MN
Solving (c): 
Substitute values for LN and LM
Solving (d): 
Substitute values for LM and LN
