Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
Answer:
91 hours
Step-by-step explanation:
Add 12 to itself 8 times and then add 7 once
Answer:
5(2x^5 + x^2 - 3)
Step-by-step explanation:
The only factor in common is 5, so you would have 5(2x^5 + x^2 - 3). That can't be factored further. IF the equation had been to the fourth degree on the first term rather than to the fifth degree, it could have been factored as 5(2x^2 -3)(x^2 +1).
Answer:
0.43
Step-by-step explanation:
Just take out the % sign and divide it by 100.
For your example:
43%
Take out the percentage
43
Divide it by 100.
0.43
And there is your answer :)
Let the amount deposited by each of them in march be m.
in April, Isaiah deposited 210$, this means the amount in his account became m+210
Freddie increased the amount by 15%, this means that the amount of money in his account became: m+0.15m
since both values are still equal, we will equate both equations and solve for m.
m+210 = m+0.15m
0.15m = 210
m = 1400$
