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2 years ago

Select the correct answer. Which equation, when solved, gives 8 for the value of x?

Mathematics

1 answer:

Rus_ich [418]2 years ago

8 0

The 3rd equation, as if you solve for x as shown, you will end up with equation x=8.

$\frac{5}{4}x-\frac{3}{2}x=-4+2$

$\frac{5}{4}x-\frac{6}{4}x=-2$

$-\frac{1}{4}x=-2$

$x=8$

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A single card is drawn from a deck. Find the probability of selecting

shepuryov [24]

Answer:

A. 1/2.

B. 15/26.

Step-by-step explanation:

Note when you have an 'OR' in the statement we add the probabilities.

A . Club or a diamond . There are 13 clubs and 13 diamonds so

The Required Probability = 13/52 + 13/52

= 1/4 + 1/4 = 1/2.

B. There are 4 jacks and 26 black cards.

The Required Probability = 4/52 + 26/52

= 1/13 + 1/2

= 2/26 + 13/26

= 15/26.

5 0

3 years ago

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: ordinary differential equation ode integration separable variables initial value problem differential integral calculus

7 0

3 years ago

I NEED HELP-AGAIN PLEASE ASAAAPPPP Ok its the question that i attached guys please asap...

LenKa [72]

Answer:

since you have a google browser type the following equation into the bar without searching for it.

Step-by-step explanation:

the instructions or search online.

8 0

2 years ago

What is the standard form of this number? 700,000 + 30,000 + 1,000 + 40 + 6

slega [8]

Answer:

731 046

Step-by-step explanation:

put the unit it it's correct value position

7 0

2 years ago

!NEED HELP URGENTLY! p − 10p + -5p + 14p − -9p − 2 = -20

bekas [8.4K]

Answer:

p = -2

Step-by-step explanation:

p − 10p + -5p + 14p − -9p − 2 = -20

-9p + 9p + 9p = -20 + 2

9p = -18

p = -2

7 0

2 years ago

Select the correct answer. Which equation, when solved, gives 8 for the value of x?​

Select the correct answer. Which equation, when solved, gives 8 for the value of x?