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3 years ago

Help ASAP thank you!! And show work !

Mathematics

1 answer:

RUDIKE [14]3 years ago

6 0

Answer:

c. -2

Step-by-step explanation:

Since f(x) is the regular graph. Since the inverse function flips the x and y coordinates, f inverse of 4 is actually where y=4, not x=4. so the x coordinate where y is 4 is -2.

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Find the perimeter of a rectangle that is 2 and 1/2 yards by 4 and 1/2 yards

Travka [436]

The answer is 14. First, get both numbers and add them twice (2.5+2.5+4.5+4.5) or (2.5 * 2 + 4.5 * 2). Then you should get 2 numbers which are 9 and 5. Then it should be 14, which is the answer.

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3 years ago

CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM PLEASE????????????????????????

icang [17]

Answer:

For 1 there is causationand there is correlation because they found that if people have a higher income, they will buy a more expensive plan so one cause another

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3 years ago

(1) (10 points) Find the characteristic polynomial of A (2) (5 points) Find all eigenvalues of A. You are allowed to use your ca

Yuri [45]

Answer:

Step-by-step explanation:

Since this question is lacking the matrix A, we will solve the question with the matrix

$\left[\begin{matrix}4 & -2 \\ 1 & 1 \end{matrix}\right]$

so we can illustrate how to solve the problem step by step.

a) The characteristic polynomial is defined by the equation $det(A-\lambdaI)=0$ where I is the identity matrix of appropiate size and lambda is a variable to be solved. In our case,

$\left|\left[\begin{matrix}4-\lamda & -2 \\ 1 & 1-\lambda \end{matrix}\right]\right|= 0 = (4-\lambda)(1-\lambda)+2 = \lambda^2-5\lambda+4+2 = \lambda^2-5\lambda+6$

So the characteristic polynomial is $\lambda^2-5\lambda+6=0$ .

b) The eigenvalues of the matrix are the roots of the characteristic polynomial. Note that

$\lambda^2-5\lambda+6=(\lambda-3)(\lambda-2) =0$

So $\lambda=3, \lambda=2$

c) To find the bases of each eigenspace, we replace the value of lambda and solve the homogeneus system(equalized to zero) of the resultant matrix. We will illustrate the process with one eigen value and the other one is left as an exercise.

If $\lambda=3$ we get the following matrix

$\left[\begin{matrix}1 & -2 \\ 1 & -2 \end{matrix}\right]$ .

Since both rows are equal, we have the equation

$x-2y=0$ . Thus x=2y. In this case, we get to choose y freely, so let's take y=1. Then x=2. So, the eigenvector that is a base for the eigenspace associated to the eigenvalue 3 is the vector (2,1)

For the case $\lambda=2$ , using the same process, we get the vector (1,1).

d) By definition, to diagonalize a matrix A is to find a diagonal matrix D and a matrix P such that $A=PDP^{-1}$ . We can construct matrix D and P by choosing the eigenvalues as the diagonal of matrix D. So, if we pick the eigen value 3 in the first column of D, we must put the correspondent eigenvector (2,1) in the first column of P. In this case, the matrices that we get are

$P=\left[\begin{matrix}2&1 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}3&0 \\ 0 & 2 \end{matrix}\right]$

This matrices are not unique, since they depend on the order in which we arrange the eigenvalues in the matrix D. Another pair or matrices that diagonalize A is

$P=\left[\begin{matrix}1&2 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}2&0 \\ 0 & 3 \end{matrix}\right]$

which is obtained by interchanging the eigenvalues on the diagonal and their respective eigenvectors

4 0

2 years ago

To the nearest tenth which choice is length of ac

xz_007 [3.2K]

Answer:

there is no photo

Step-by-step explanation:

but to answer the question for example: 0.04 would round down to the nearest tenth 0.0 and 0.05 would round up to 0.1 . So if the number is 5 or above round up or if it is 4 or below round down, hope this helps

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2 years ago

What is the percent error for a measurement of 5 yards?

Ilia_Sergeevich [38]

The percent error is 2%

3 0

2 years ago