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tankabanditka [31]
3 years ago
8

There are 12 idiots and 18 morons in Mr Lasseter math class to form groups each group must have the same number of idiots and th

e same number of morons what is the greatest number of groups mr lasseter can make if every student must be in the group
Mathematics
2 answers:
lilavasa [31]3 years ago
8 0

Answer:

6

Step-by-step explanation:

because it's the greatest common factor between 12 and 18

WARRIOR [948]3 years ago
3 0

Answer:

6

Explanation:

The amounts of idiots and morons both have a common factor of 6 and 3. Since 6 is the greater factor, it provides the most sustainable answer.

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Does anyone know how to solve this? It’s really starting to stress me out.
bekas [8.4K]

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π − 12

Step-by-step explanation:

lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

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Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

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lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

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Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

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3 years ago
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