Note: I didn't solve all of them, but hopefully this still helps.
4.
h*b = b*h because of the commutative property. for example if h= 3 and b = 5, 5*3 = 15 = 3*5
2.
a) 2x + 20
b) 5x + 5
c) 10x + 20
d) 72 + 36y
e) 64 + 72
f) 35y + 30
5.
a) 10x + 10y + 10
b) 12x + 20y + 4
c) 56x + 24y + 16
Goodluck with your schoolwork/homework!
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Apologies in advance for any errors or bad explanations.
Ans: Option A
Explanation:Let's solve it smartly!
Given expression:
--- (A)
Factors: (x+p)(x+q)
Condition: c<0
Now let us expand (x+p)(x+q):
=>
--- (B)
By comparing (B) with (A), we can say that:
pq = c --- (C)
Now, as the condition says,
c<0, it means either p or q is negative. Both cannot be positive or both cannot be negative.
1) If p>0, q>0, it means c>0 since (+p)(+q) = (+c)(according to equation (C)). Condition is not met.
Hence, option B and D are wrong.
2) If p<0, q<0 it means c>=0 since (-p)(-q) = (+c)(according to equation (C)). Condition is not met.
Hence option C is out as well.
We are left with Option A:
p<0, q>0 it means c<0 since (-p)(+q) = (-c)(according to equation (C)). Condition is MET!
Hence,
Ans: Option A: p= -3, q= 7
Answer: C
Step-by-step explanation:
See attached image.
Answer:
2/9 times
Step-by-step explanation:
This is because 2/5 divided by 9/10 = 10/45 wich if we simplify it we get 2/9 so that's why 2/9 is the right answer.
(brainley please)
Answer: √10, √27, and √99 are all the irrational numbers from the list.
√10 = √(5*2) = √5 * √2 ----> irrational
√27 = √(9*3) = (√9) * √(3) = 3√3 ----> irrational
√99 = √(9*11) = (√9) * (√11) = 3√11 -------> irrational
√(49) = 7 -----> rational
√(64) = 8 ----------> rational