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kari74 [83]
3 years ago
5

Which line of code will find the first occurrence of a three in an array?

Computers and Technology
2 answers:
eduard3 years ago
5 0
Arr.index[3] is most likely true
motikmotik3 years ago
3 0

Answer:

It is arr.index(3)

Explanation:

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The full meaning of ENIAC,ABACUS,EDVAC,EDSAC<br>and explain ​
balandron [24]

Answer:

ENIAC: Electronic Numerical Integrator and Computer.

ABACUS: Abundant Beads, Addition and Calculation Utility System.

EDVAC: Electronic Discrete Variable Automatic Computer

EDSAC: Electronic Delay Storage Automatic Computer

7 0
3 years ago
2) [13 points] You’ve been hired by Banker Bisons to write a C++ console application that determines the number of months to rep
Paha777 [63]

Answer:

Check the explanation

Explanation:

CODE:

#include <iostream>

#include <iomanip>

using namespace std;

double getLoanAmount() { // functions as per asked in question

double loan;

while(true){ // while loop is used to re prompt

cout << "Enter the car loan amount ($2,500-7,500): ";

cin >> loan;

if (loan>=2500 && loan <= 7500){ // if the condition is fulfilled then

break; // break statement is use to come out of while loop

}

else{ // else error message is printed

cout << "Error: $"<< loan << " is an invalid loan amount." << endl;

}

}

return loan;

}

double getMonthlyPayment(){ // functions as per asked in question

double monthpay;

while(true){ // while loop is used to re prompt

cout << "Enter the monthly payment ($50-750): ";

cin >> monthpay;

if (monthpay>=50 && monthpay <= 750){ // if the condition is fulfilled then

break; // break statement is use to come out of while loop

}

else{ // else error message is printed

cout << "Error: $"<< monthpay << " is an invalid monthly payment." << endl;

}

}

return monthpay;

}

double getInterestRate(){ // functions as per asked in question

double rate;

while(true){ // while loop is used to re prompt

cout << "Enter the annual interest rate (1-6%): ";

cin >> rate;

if (rate>=1 && rate <= 6){ // if the condition is fulfilled then

break; // break statement is use to come out of while loop

}

else{ // else error message is printed

cout << "Error: "<< rate << "% is an invalid annual interest rate." << endl;

}

}

return rate;

}

int main() {

cout << setprecision(2) << fixed; // to print with 2 decimal places

int month = 0; // initializing month

// calling functions and storing the returned value

double balance= getLoanAmount();

double payment= getMonthlyPayment();

double rate= getInterestRate();

rate = rate /12 /100; // as per question

// printing as per required in question

cout << "Month Balance($) Payment($) Interest($) Principal($)"<< endl;

while(balance>0){ // while the balance is more than zero

month = month + 1; // counting Months

// calculations as per questions

double interest = balance * rate;

double principal = payment - interest;

balance = balance - principal;

// printing required info with proper spacing

cout <<" "<< month;

cout <<" "<< balance;

cout <<" "<< payment;

cout <<" "<< interest;

cout <<" "<< principal << endl;

}

cout << "Months to repay loan: " << month << endl; // displaying month

cout << "End of Banker Bisons";

Kindly check the output in the attached image below.

5 0
3 years ago
A(n) __________ is a common list operation used in programming. Its purpose is to iterate through a list of items, one item at a
34kurt
Linear search

You implement this algorithm by iterating over each item, and checking if the item matches what you are searching for.

It is linear because it takes a linear amount of time to search for an item.
5 0
3 years ago
Write a calculator program that will allow only addition, subtraction, multiplication &amp; division. Have the
ozzi

num1 = float(input("Enter the first number: "))

num2 = float(input("Enter the second number: "))

operation = input("Which operation are you performing? (a/s/m/d) ")

if operation == "a":

   print("{} + {} = {}".format(num1, num2, num1+num2))

elif operation == "s":

   print("{} - {} = {}".format(num1, num2, num1-num2))

elif operation == "m":

   print("{} * {} = {}".format(num1, num2, num1*num2))

elif operation == "d":

   print("{} / {} = {}".format(num1, num2, num1/num2))

I hope this helps!

8 0
3 years ago
Why was packet-switching an advancement over previous forms of networking?
Elina [12.6K]

The answer should be B tell me if I'm wrong.


8 0
3 years ago
Read 2 more answers
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