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Fudgin [204]
4 years ago
11

The scheme function (mult2-diff Ist) should take one argument, a list of numbers, and results in multiplying each number in the

list by two and then computing the difference of those numbers, e.g.: (mult2-diff'(912)) should evaluate to the difference of 18, 2 and 4: (18-2)-4, or 12. Finish mult2-diff below: (define (mult2-diff lst) (if
Computers and Technology
1 answer:
JulijaS [17]4 years ago
6 0

Answer:

The solution code is written in Python.

  1. def mult2_diff(lst):
  2.    num_list = []
  3.    for x in lst:
  4.        num_list.append(x * 2)
  5.    diff = num_list[0]
  6.    for i in range(1, len(num_list)):
  7.        diff = diff - num_list[i]
  8.    
  9.    print(diff)

Explanation:

Firstly, based on the requirement stated in the question, define a function <em>mult2_diff() </em>that takes one argument, <em>lst</em>, which is a list of numbers (Line 1).

This function is expected to multiply each number in the list by two and then followed with computing the difference. To do so, let's try to attempt the first function task, multiplying numbers.  Create a new list, num_list, to hold the multiplied numbers (Line 2). Use a for loop to traverse through each number in the input list, <em>lst</em>, and multiply each of them by two and add it to the <em>num_list </em>(Line 4-5).

To attempt the second function task, create another variable, <em>diff</em>, to hold the value of calculated difference between the numbers in the <em>num_list</em>. Initialize <em>diff </em>with the first number in the <em>num_list</em>. Use a another for-loop to traverse through each number in the num_list starting with second index, <em>1</em>, and calculate the difference between the <em>diff </em>and the current number extracted from the <em>num_list </em>through indexing.

At last print the output of <em>diff</em> (Line 11).

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Answer:

// here is code in java.

import java.util.*;

class Solution

{

// main method of class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // declare variable

         double caffeine;

    // scanner object to read input from user

       Scanner scr=new Scanner(System.in);

       System.out.print("Enter the initial amount of caffeine:");

        // read the initial amount of caffeine

           caffeine=scr.nextDouble();

          // calculate amount of caffeine after 6,12,18 hours

          for(int i=1;i<=3;i++)

          {

               System.out.println("After "+ i*6+" hours:"+(caffeine/2)+" mg");

               // update the caffeine after every 6 hours

               caffeine=caffeine/2;

          }

                 

   }catch(Exception ex){

       return;}

}

}

Explanation:

Create a variable "caffeine" to store the initial amount of caffeine given by user. Run a loop for three time, it will calculate the amount of caffeine left after every 6 hours.First it will give the amount of caffeine left after 6 hours, then caffeine left after 12 hours and in last caffeine after 18 hours.

Output:

Enter the initial amount of caffeine:100

After6 hours:50.0 mg

After12 hours:25.0 mg

After18 hours:12.5 mg

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3 years ago
In a mobile phone network, how many times as strong would
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Answer:

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Explanation:

May I have brainliest please? :)

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3 years ago
Given: an int variable k, an int array current Members that has been declared and initialized, an int variable memberID that has
Alekssandra [29.7K]

Answer:

The c++ program is given below. Nothing is displayed as per the question.

#include <iostream>

using namespace std;

int main() {    

   // declaration and initialization of integer variables

   int k, memberID = 12, nMembers=5;

   bool isAMember;    

   // declaration and initialization of integer array

   int currentMembers[] = {12, 34, 56, 78, 90};    

   for(k=0; k<nMembers; k++)

   {

       if(memberID == currentMembers[k])

       {

           // when member is found in the array, the loop is exited using break

           isAMember = true;

           break;

       }

       else

           isAMember = false;

   }    

   return 0;

}

Explanation:

The program begins with declaration and initialization of integer variables and followed by initialization of the array holding the id of all the members.

The Boolean variable is declared but not initialized.

int k, memberID = 12, nMembers=5;

bool isAMember;

int currentMembers[] = {12, 34, 56, 78, 90};

After this, the array holding the id of the members is searched for the given member id. This is done using  a for loop and a if else statement inside the loop.

If the member id is present in the array, the variable isAMember is initialized to true otherwise it is assigned false.

When the variable isAMember is initialized to true, the break statement is used to exit from the loop.

for(k=0; k<nMembers; k++)

   {

       if(memberID == currentMembers[k])

       {

           isAMember = true;

           break;

       }

       else

           isAMember = false;

 }

The break is used since other values of id in the array will not match the given member id and the variable, isAMember will be initialized to false even if the given member id is present in the array. Hence, it is mandatory to exit the loop once the given member id is found in the array.

This program can be tested for different values of the id of the members and different sizes of the array.

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