Question

A fireman's water hose shoots 320 kg of water each second against the door of a building. The velocity of the water is 20 m/s and the water strikes the door horizontally and doesnt bounce back. What average force is exerted by the stream of water?

Answer 1

Answer:

$6400\ \text{N}$

Step-by-step explanation:

$\dfrac{m}{t}$ = Mass flow rate of water = 320 kg/s

$m$ = Mass of water on the door

$t$ = Time

$v$ = Velocity of water on the door = 20 m/s

Force is given by

$F=\dfrac{m}{t}v\\\Rightarrow F=320\times 20\\\Rightarrow F=6400\ \text{N}$

The average force is exerted by the stream of water is $6400\ \text{N}$.