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topjm [15]
3 years ago
6

Find the slope plllls I need help

Mathematics
2 answers:
STatiana [176]3 years ago
8 0

Answer:

the slope is 5/4

lubasha [3.4K]3 years ago
5 0

Answer: 5 over 5

Step-by-step explanation:

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For the expression 6 − y + 3, determine the coefficient for the variable term.
sergij07 [2.7K]

<span>6 − y + 3 

-y = (-1) (y)

so answer is </span><span>−1</span>
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4 years ago
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Help me please i really need it
Sauron [17]

Answer:

Multiply each number by the little number next to it then add. It will be a huge number.

Step-by-step explanation: Above.

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2 years ago
The price of product A as a function of time is given by the function f(t). Similarly, the function g(t) represents the price of
jok3333 [9.3K]

Answer:

Step-by-step explanation:

Recall that a function f is concave up if it's second derivative is positive and it is concave down if it's second derivative is negative. Recall that the second derivative tell us how the first derivative is behaving. Thus, if the second derivative is positive, then the first derivative is increasing as the time passes. If the second derivative is negative, that means that the first derivative is decreasing as the time passes.

Consider the product A with a price function that is concave up. This means that the first derivative is constantly increasing. This means, that if the price of the product A is decreasing, it will decrease less and less until it starts to increase. If on the contrary the price is already increasing, it will keep on increasing at a higher rate.

Consider the product B with a price function that is concave down. This means that the first derivative is constantly decreasing. So, if the price is increasing, it will increase less and less until it starts decreasing, or if it is already decreasing it will keep decreasing at a higher rate

8 0
3 years ago
Find r(t) if r'(t) = 5t4i + 6t5j + t k and r(1) = i + j.
Vladimir [108]
\mathbf r(t)=\displaystyle\int(5t^4\,\mathbf i+6t^5\,\mathbf j+t\,\mathbf k)\,\mathrm dt
\mathbf r(t)=(t^5+C_1)\,\mathbf i+(t^6+C_2)\,\mathbf j+\left(\dfrac12t^2+C_3\right)\,\mathbf k

Given \mathbf r(1)=\mathbf i+\mathbf j, we have

\begin{cases}1^5+C_1=1\\\\1^6+C_2=1\\\\\dfrac121^2+C_3=0\end{cases}\implies C_1=0,C_2=0,C_3=-\dfrac12

so that the particular solution is

\mathbf r(t)=t^5\,\mathbf i+t^6\,\mathbf j+\dfrac12(t^2-1)\,\mathbf k
8 0
3 years ago
True or False? A direction angle will always be a value between -90° and 90°.
Artist 52 [7]

Answer:

  False

Step-by-step explanation:

The short reason the statement is false is, "it depends on what you mean by <em>direction angle</em>".

The long reason the statement is false is that "direction angle" sometimes refers to a navigation direction that is specified in terms of compass directions. For example, you might have N20°E, or S80°E. The angle measure in such directions is 0 to 90°. It does not take on a negative value when the direction is expressed in the standard form, an angle east or west from north or south.

An arbitrary vector is an expression that has a magnitude and direction. Such a quantity can have either or both values be positive or negative and of <em>any magnitude</em>. There is no reason for direction to be restricted to values in the range ±90°.

8 0
3 years ago
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