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harina [27]
3 years ago
8

What is the domain of the function graphed below?

Mathematics
2 answers:
Darina [25.2K]3 years ago
7 0

The domain of the function graphed is x . Option (a) is correct.

Further explanation:

Domain is a set of all the possible values of the function. The value at which the function is defined is known as domain.

Range is a set of values that the function takes.

The output values of the function are known as range and the input values on which function is defined is known as the domain of the function.

Explanation:

The function can’t take the values greater than 7 or equal to 7.

The function is defined for the values of x less than 7. Therefore the domain of the function is x .

The domain of the function graphed is x . Option (a) is correct.

Option (a) is correct as the domain of the graphed function is x .

Option (b) is not correct as the domain of the graphed function is x .

Option (c) is not correct as the domain of the graphed function is x .

Option (d) is not correct as the domain of the graphed function is x .

Learn more:

1. Learn more about inverse of the function <u>brainly.com/question/1632445</u>.

2. Learn more about equation of circle <u>brainly.com/question/1506955</u>.

3. Learn more about range and domain of the function <u>brainly.com/question/3412497 </u>

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Functions

Keywords: range, domain, codomain, relation, function, graph, coordinates, close interval, open interval, values.

valkas [14]3 years ago
5 0
The function is defined over these ranges of x:
(-∞, -1) and [-1, 7), that is for x < 7.

Note that
The function is undefined at x = --1 over the left portion of the straight line, but the function s defined at x = -1 for the right portion f the straight line.
The function is undefined at x = 7 and for larger values of x.

Answer: x < 7
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3 years ago
If x+y=5,x-y=4,find the value of x²-y²​
inysia [295]

Answer:

20

Step-by-step explanation:

→ First find the value of x and y

x + y = 5

x - y = 4

→ Add the equations to cancel out the y's

2x = 9

→ Divide both sides by 2 to find the value of x

x = 4.5

→ Substitute x = 4.5 back into x - y = 4 to find the value of y

4.5 - y = 4

→ Minus 4.5 from both sides to isolate -y

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→ Multiply everything by -1

y = 0.5

→ Substitute x = 4.5 and y = 0.5 into x² - y²

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3 years ago
Write the equation in standard form for the circle with center (0, – 10) and radius 6.
Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: (x-h)^2+(y-k)^2=r^2

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

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So, equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

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