The interval of the convergence is x < -3 or x > 3 if the series n 3^n/x^n goes infinitely.
<h3>What is convergent of a series?</h3>
A series is convergent if the series of its partial sums approaches a limit; that really is, when the values are added one after the other in the order defined by the numbers, the partial sums getting closer and closer to a certain number.
We can find the interval for the convergent by root test.
Like the Ratio Test, the root Test is used to determine absolute convergence (or not) with factorials, the ratio test is useful.
For the given series:

As the series goes infinitely, we can use root test.
By the root test, the convergence interval will be;
The interval of convergence is:
x < -3 or x > 3 we can write this as:
|x| < 3
Thus, the interval of the convergence is x < -3 or x > 3 if the series n 3^n/x^n goes infinitely.
Learn more about the convergent of a series here:
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Answer:
The correct option is B
(-1)(1/2)(-1)(1)
Step-by-step explanation:
First thing to notice is that there is are two brackets with negative values, which means that the result must also be positive (or have two brackets with negative values).
Looking at the options, we can screen out options A and D, they have three brackets with negative values, and can't be chosen.
It is now between options B and C.
Option B, by inspection is simply 1/2
Option C is 12/4 = 3
The problem itself is 12/35
12/24 = 1/2
12/36 = 1/3
Since 12/35 is about 1/3, it is closer to 1/2 than 3, so 1/2 is the best option.
-0.183 = -0.183 / 1
Numerator = -0.183 × 10 × 10 × 10 = -183
Denominator = 1 × 10 × 10 × 10 = 1000
Numerator / Denominator = -183 / 1000
Our simplified fraction is:
= -183/1000
Answer:
x
Step-by-step explanation: