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Jet001 [13]
3 years ago
13

Find the perimeter of the figure below. ​

Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer:

ur ans is B) 96mm

Step-by-step explanation:

If it's ok...PLZ mark it as brainliest

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Several batches of stew were made yesterday. Each batch required 1 and two-thirds pounds of meat. All together, 10 and StartFrac
katovenus [111]

Answer:

Janice converted a mixed number to the wrong improper fraction.

Step-by-step explanation:

1 batch of stew uses 1 and 2/3 lb meat

Total amount of meat used - 10 and 5/6 lb

x = number of stew batches made

To get number of batches made, divide total meat used by the amount of meat each batch requires:

x = 10 5/6 ÷ 1 2/3

convert mixed fractions to improper fractions:

x = (10x6+5)/6 ÷ (1x3+2)/3

x = 65/6 ÷ 5/3

The fraction in bold numbers is where Janice got it wrong. She changed 1 2/3 to 5/2. (From the question: 10 and StartFraction 5 over 6 EndFraction divided by 1 and two-thirds = StartFraction 65 over 6 EndFraction divided by five halves). 1 2/3 converted to an improper fraction is 5/3. From this point going forward, the calculations are wrong.

8 0
3 years ago
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Can someone answer this question please?
Setler [38]

Answer:

yes...

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yes...

7 0
3 years ago
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Help me asap! I will give you marks
Law Incorporation [45]

Recall the binomial theorem.

(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k

1. The binomial expansion of \left(1+\frac x3\right)^7 is

\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}

Observe that

k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x

k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2

When we multiply these by 8-9x,

• 8 and \frac73 x^2 combine to make \frac{56}3 x^2

• -9x and \frac73 x combine to make -\frac{63}3 x^2 = -21x^2

and the sum of these terms is

\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}

2. The binomial expansion is

\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k

We get the a^6b^2 term when k=2 :

k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2

6 0
1 year ago
Wayne used the diagram to compute the distance from Ferris, to Dunlap, to Butte. How much shorter is the distance directly from
Dmitry_Shevchenko [17]
Because the triangle is a right angle, the hypotenuse is the square root of the sum of the legs squared or the square root of (20 ^2 + 15^2) or 25. The distance wayne computed was the distance from Ferris to Dunlap or 15 plus the distance from Dunlap to Butte or 20 or 35 miles all together. The difference of 35 and 25 is 10
4 0
3 years ago
What is the simplified form of ?
Natalija [7]
Let's set it up like this:
\frac{\frac{x}{3}-\frac{y}{4}}{\frac{x}{4}+\frac{y}{3}}
Find the LCD, which is 12, and adjust them according to that.
=\frac{\frac{4x-3y}{12}}{\frac{3x+4y}{12}}
Divide.
=\frac{\left(4x-3y\right)\cdot \:12}{12\left(3x+4y\right)}
Cancel the common factor, which is 12.
=\frac{4x-3y}{3x+4y}
That would be our answer!

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish
5 0
4 years ago
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