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e-lub [12.9K]
3 years ago
12

A rock falls from rest a vertical distance of 0.72 meter to the surface of a planet in 0.63 second. What is the magnitude of the

acceleration due to gravity on the planet?
Mathematics
1 answer:
Reika [66]3 years ago
6 0
The question is asking to calculate the magnitude of the acceleration due to gravity on the planet and base on the given of the problem and in my further calculation, the magnitude would be 3.638 m/s^2. I hope you are satisfied with my answer and feel free to ask for more 
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What is the equation of the following line? Be sure to scroll down first to see
Rom4ik [11]
<h2>Answer:</h2>

-1/3x

<h2>Step-by-step explanation:</h2><h3>Known :</h3>
  • x1 = -3
  • x2 = 0
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<h3>Asked :</h3>
  • Correct line equation

<h3>Solution :</h3>

We can find the straight line equation using this formula,

\frac{y-y1}{y2-y1} = \frac{x-x1}{x2-x1}

Insert all we know inside the formula,

\frac{y-1}{0-1} = \frac{x-(-3)}{0-(-3)}\\\frac{y-1}{-1} = \frac{x +3}{3}\\

Use cross multiplication,

3(y - 1) = -1(x + 3)\

3y - 3 = -x - 3

3y = -x - 3 + 3

3y = -x

y = -1/3x

<h3>Conclusion :</h3>

The correct equation is y = -1/3x

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