Answer:
39
Step-by-step explanation:
Given the function :
h(t) = t² + 2
From t = 5 to t = 8
when, t = 5
h(5) = 5² + 2
h(5) = 25 + 2
h(t) at t = 5 ; equals 27
when, t = 8
h(5) = 8² + 2
h(5) = 64 + 2
h(t) at t = 8 ; equals 66
Net Change :
h(8). - h(5)
66 - 27 = 39
Answer:
3rd choice
Step-by-step explanation:
(7y^6)(2y^-4)^2
= (7y^6)(4y^-8)
Calculate:
(7y^6) * (4y^-8)
28y^-2
Express with a positive exponent:
28 * 1/y^2
Answer:
Linear functions change at a constant rate per unit interval. An exponential function changes by a common ratio over equal intervals.
