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pshichka [43]
3 years ago
15

Expand the expression 9(2t-8)

Mathematics
1 answer:
borishaifa [10]3 years ago
7 0

Answer:

18t-72

Step-by-step explanation:

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Two linear functions are shown. Which function has the greater initial​ value?
tangare [24]

Answer:

Function A has the greater initial value because the initial value for Function A is 6 and the initial value for Function B is 3.

Step-by-step explanation:

✔️Function A:

Initial value = y-intercept (b)

y-intercept is the value of y, when the corresponding value of x = 0

From the table, y = 6 when x = 0.

The y-intercept of function A = 6

Therefore, initial value for Function A = 6

✔️Function B:

y = 4x + 3 is given in the slope-intercept form, y = mx + b.

b = y-intercept = initial value.

Therefore

Initial value for Function B = 3

✔️Function A has the greater initial value because the initial value for Function A is 6 and the initial value for Function B is 3.

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A 650-pund snowmobile trailer is sitting on an exit ramp inclined at 40 degrees
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20 POINTS
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Ni is not correct. To solve the equivalent quarterly interest rate, the annual interest rate should be multiplied by the correct ratio. Since the annual interest rate is 4% per year. So in 1 quarter is equal to 0.25 year.

<span>(4% / year) (0.25 year/ 1 quarter) = 1% per quarter</span>

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Find the squre of 17<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B17%7D%20" id="TexFormula1" title=" \sqrt{17} " alt=" \sqr
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The answer is 4.12310562562
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Match the information on the left with the appropriate equation on the right.
solmaris [256]

Answer:

Step-by-step explanation:

1). Equation of a line which has slope 'm' and y-intercept as 'b' is,

y = mx + b

If slope 'm' = 1 and y-intercept 'b' = -3

Equation of the line will be,

y = x - 3

x - y = 3

2). Equation of a line having slope 'm' and passing through a point (x', y') is,

y - y' = m(x - x')

If the slope 'm' = 1 and point is (-1, 2),

The the equation of the line will be,

y - 2 = 1(x + 1)

y = x + 1 + 2

y = x + 3

x - y = -3

3). Equation of a line passing through two points (x_1, y_1) and (x_2,y_2) will be,

y-y_1=\frac{(y_2-y_1)}{(x_2-x_1)}(x-x_1)

If this line passes through (-2, 3) and (-3, 4),

y-3=\frac{(4-3)}{(-3+2)}(x+2)

y - 3 = -1(x + 2)

y = -x - 2 + 3

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3 years ago
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