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sertanlavr [38]

1 year ago

13

The figure shows how a leaf meets the stem of a flower to form two angles. the value of x is?

1 answer:

Ganezh [65]1 year ago

6 0

Ahh you forgot to add the image...

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there are 680 students and Cassie's High School 40% of the students are taking Spanish how many students are taking Spanish

snow_lady [41]

272

680 x 0.40 = 272

8 0

2 years ago

A factory employs several thousand workers, of whom 35% are Hispanic. If the 17 members of the union executive committee were ch

Elza [17]

Answer:

as p decreases, sigma decreases.

Step-by-step explanation:

Given that 35%are hispanic. For a sample of 17 members

n = 17

p = 0.35

and the number of Hispanics on the committee would have the binomial distribution

a) Mean of X = E(x) = $np = 17(0.35)\\= 5.95$

b) Std dev X = $\sqrt{npq} =\sqrt{5.95(0.65)} \\=1.9665$

c) Here n =17 and p =0.1

$Mean = 1.7\\\sigma = \sqrt{17(0.1)(0.9)} =1.234$

d) When p = 0.01

$Mean = 0.17\\\sigma = 0.410$

Thus we find that as p decreases, sigma decreases.

8 0

2 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

Write the number 254 as a sum of hundreds,tens,and ones

Aloiza [94]

200+50+4=254 is the answer

5 0

2 years ago

Read 2 more answers

Help me please on this

amid [387]

I do believe the answer is 52, sorry if i’m incorrect

4 0

2 years ago