First step- convert the mixed numbers into improper fractions
second step- make sure the improper fractions have the same denominator
last step, add/subtract the two fractions and simplify if possible
No, a cubic equation can not have three complex roots. This is because it turns twice and one end goes to positive infinity and one end goes to negative infinity. Thus, one of these MUST cross the x-axis at some point, meaning y = 0 and a real root exists.
Yes, a cubic equation can have three real roots if it cuts the x-axis three times.
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The number is 16
PS: had to type more than 20 words
Answer:
2/9
Step-by-step explanation:
B
HOPE IT HELPS HAVE A GREAT DAY
If you're looking for the Euclid Algorithm, try going with these ↓
137 - ( 27 × 5) = 2
27 - ( 2 × 13) = 1
2 - (1 × 2) = 0
GCF → 1