Answer:
f is not defined at x = 3 ⇒ answer (b)
Step-by-step explanation:
∵ f(x) = x² - x - 6/x² - 9 is a rational function
∴ It will be undefined at the values of x of the denominator
∵ The denominator is x² - 9
∵ x² - 9 = 0 ⇒ x² = 9 ⇒ x = ±√9
∴ x = ± 3
∴ f(x) can not be defined at x = 3
∴ The f(x) can not be continuous at x = 3
∴ The answer is (b)
Answer:
Step-by-step explanation:
(X+4)1999=1
Open the bracket by multiplying 1999 by the values in the bracket
1999x + 7996 = 1
Collect like terms
1999x = 1-7996
1999x = -7995
Divide both sides by 1999
X = -3.99
If you look at the graph of sin(n), you can notice that it oscillates every kpi/2 when k is odd. This oscillation proves that sin(n) diverges.
Answer: yes
Step-by-step explanation: Joshua
The modulus of complex number can be computed with this equation:
|z|=sqrt(Re(z)^2+Im(z)^2)
z = -2-6i
Re(z)=-2, so Re(z)^2=4
Im(z)=-6, so Im(z)^2=36
|z|=sqrt(36+4)=sqrt(40)=6.3