Answer:
(x + 14)² + (y – 21/2)² = 1
Step-by-step explanation:
The equation of a circle can be written as seen below
(x – h)² + (y – k)² = r²
Where (h,k) is at the center and r = radius
We are given that the radius is 1
We are also given that the center is at (-14,21/2)
So we know that r = 1, h = -14, and k = 21/2
So to find the equation of the circle we simply substitute these values into the equation of a circle
Equation of a circle: (x – h)² + (y – k)² = r²
r = 1, h = -14, and k = 21/2
Substitute values
(x – (-14))² + (y – 21/2)² = 1²
1^2 = 1
The two negative signs before the 14 cancel out and it changes to + 14
The equation of a circle with a center at (-14,21/2) and a radius of 1 is (x + 14)² + (y – 21/2)² = 1
Answer: |-10| < |11|
So choice C. is right.
hope this helps!
If the polynomial is of the form x^2+bx+c (ie., no factor in front of the x^2!!) then you can look for numbers that add up to b and multiply to c.
So in this case: what two numbers, when added, give -2 and when multiplied, give 1? A little trial and error gives you -1 and -1.
So the factorization is (x-1)(x-1). This is zero for x=1. There is only one zero.
Answer:
y = 3x + 22
Step-by-step explanation:
y - 7 = 3(x+5)
Distribute,
y - 7 = 3x + 15.
Add 7 to both sides.
Final answer, y = 3x + 22.
Hope this helps!
do you want an explanation too or just the answer anyway here's the answer 488
