All categories

3 years ago

Determine whether the relation is a function. quick EMERGENCY I NEED HELP

Mathematics

1 answer:

saul85 [17]3 years ago

6 0

Not a function.
It goes from -1=-4 to -1=-2

You might be interested in

Equivalent equation for m-28=21

aalyn [17]

Hello! So I understood your question as what M means. M is 49, 49-28=21

6 0

2 years ago

Х- 1, 2, 3 ,4

Len [333]

I think it’s C, good luck

4 0

2 years ago

Write the slope-intercept form of the equation of the line that is perpendicular to AB and passes through Point X. Show all work

aleksandr82 [10.1K]

Answer:

Equation of line is y=(12/5)x+2

Step-by-step explanation:

The slope of line AB is -5/12. The line passing X is perpendicular to line AB and hence have a slope of 12/5. The slope intercept form is given by y=mx+c.

Now, point X satisfies the equation. Plugging in the slope of the line we end up with

y=(12/5)*x+c, now to find c

-10=(12/5)*(-5)+c, c=2

Equation of line is y=(12/5)x+2

7 0

3 years ago

How many perfect cubes are there between 2 to 200 ?<br> ANSWER fast

Mekhanik [1.2K]

Answer:

Three

Step-by-step explanation:

The perfect cubes between 2 to 200 are

${3}^{3} = 27 \\ \\ {4}^{3} = 64 \\ \\ {5}^{3} = 125 \\$

Hence, there are only three perfect cubes 27, 64 and 125 between 2 to 200.

3 0

3 years ago

when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%

Fynjy0 [20]

She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%

Selling price = cost price - discount ⇒ discount case
Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = $\frac{160}{90}=\frac{16}{9}$

∵ She sold them with discount 20%

∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = $\frac{20}{100}$ × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

- Equate 0.8x by $\frac{16}{9}$ to find x

∵ 0.8x = $\frac{16}{9}$

- Divide both sides by 0.8

∴ x = $\frac{20}{9}$

Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is $\frac{20}{9}$

- Find 20% of $\frac{20}{9}$

∵ Profit = 20% × $\frac{20}{9}$ = $\frac{20}{100}.\frac{20}{9}=\frac{4}{9}$

- Add $\frac{4}{9}$ to cost price to find the selling price

∴ The selling price of an orange = $\frac{20}{9}$ + $\frac{4}{9}$

∴ The selling price of an orange = $\frac{24}{9}$

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ $\frac{24}{9}$

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

4 0

3 years ago

Determine whether the relation is a function. quick EMERGENCY I NEED HELP ​

Determine whether the relation is a function. quick EMERGENCY I NEED HELP