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3 years ago

How can a ratio be used to compare quantities?

Mathematics

2 answers:

photoshop1234 [79]3 years ago

8 0

Answer:

Two quantities can be compared by a ratio. As a fraction in the simplest form, a typical manner of expressing a ratio. If you compare the two numbers with distinct measuring units, this type of ratio is known as a rate. A rate is unit rate when it is 1. A rate is unit rate.

Step-by-step explanation:

netineya [11]3 years ago

3 0

Answer:

You can use a ratio to compare things for example you can compare the number of people in class, there are 6 boys and 8 girls so you will compare them like this : 6:8.

There are various ways to do this : 6/8 as a fraction, 6:8 or in words 6 to 8. You have to make sure to write it in the correct order or you will for sure not get the point.

Step-by-step explanation:

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Help me please. How to prove this ?

podryga [215]

Answer:

First, you want to divide the numerator and denominator by the cosine(x), and afterwards, it looks like this...

$\frac{tan~x+1}{tan~x-1}$

Include 45 as one of the parameters and correlate with tan.

$\frac{tan~x+tan~45}{tan~x-tan~45}$

Next, you want to multiply the numerator and denominator by the conjugate of the denominator, in this case, tan x + tan 45.

Lastly, simplify, and you have the answer as tan(45 + x)

3 0

3 years ago

You pick a card at random.

Anna [14]

I think the answer is 1/4

6 0

3 years ago

Read 2 more answers

In circle T, PTQ = RTS. What is the measure of PQ? 24° 33° 48° 66°

weqwewe [10]

Answer:

The correct option is D

66°

Step-by-step explanation:

Given that ∠PTQ ≅ ∠RTS

The measure of the arc SR = 66°

So ∠RTS = 66°

But also, ∠PTQ ≅ ∠RTS

Therefore ∠PTQ = 66°

and the measure of the arc PQ = ∠PTQ

Therefore, measure of the arc PQ is 66°.

4 0

3 years ago

What is the answer to this problem

irina1246 [14]

The answer to 4x - 5y = 24 is (6, 0).

7 0

3 years ago

HELPPPP (x-y)^3-(y-x)^2

Nat2105 [25]

Answer:

(x-y)(x-y)(x-y)= x²-yx+x²-yx-yx+y²-yx+y²

2x²-4yx+2y²

(y-x)(y-x)= y²-yx-yx+x²

y²-2yx+x²

-(y²-2yx+x²) = -y²+2yx-x²

2x²-4yx+2y²-y²+2yx-x²= x²-2yx+y²

(x−y−1)(x−y)² ≡ x³−x²+3xy²+2xy−y³−y²−3yx³

8 0

1 year ago