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velikii [3]
3 years ago
9

Solve: (w)(3w+5)=0. Multiple answers, if any, should be separated by commas. Enter only integer(s) or fraction(s).

Mathematics
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

-\frac{5}{3}

Step-by-step explanation:

Given expression:

                 (w)(3w + 5) = 0

  Expand the parentheses;

                   3w² + 5w  = 0

                    3w²  = -5w

Divide both sides by w;

                    3w  = - 5

                       w = -\frac{5}{3}

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Find a degree 3 polynomial with real coefficients having zeros 2 and 2 − 2 i and a lead coefficient of 1. Write P in expanded fo
Zanzabum

Answer:

The polynomial with real coefficients having zeros 2 and 2 - 2i is

x³ - 6x² + 16x - 16 = 0

Step-by-step explanation:

Given that a polynomial has zeros at 2 and 2 - 2i, we want to write this polynomial.

We have

x - 2 = 0

x - (2 - 2i) = 0

=> x - 2 + 2i = 0

Since the polynomial has real coefficients, and 2 - 2i is a zero of the polynomial, the conjugate of 2 - 2i, which is 2 + 2i is also a polynomial.

x - (2 + 2i) = 0

=> x - 2 - 2i = 0

Now,

P(x) = (x - 2)(x - 2 + 2i)(x - 2 - 2i) = 0

= (x - 2)((x - 2)² - (2i)²) = 0

= (x - 2)(x² - 4x + 8) = 0

= x³ - 4x² + 8x - 2x² + 8x - 16 = 0

= x³ - 6x² + 16x - 16 = 0

This is the polynomial required.

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