Answer:
Hello there, the question asked is not complete (that is the reaction is not given) and similar Question could not be found. Hence, we will go with the information given above and make little assumptions.
Explanation:
So, from the the question above there is the need to determine the theoretical yield from the given starting materials that is 10 ml of the alcohol and 10 ml of 12 molar HCl g. So, let's say the alcohol given can be any alcohol Compound.
Thus, the equation showing the reaction is given as;
HCl + ROH =====> RCl + H20.
That's one mole of HCl react with alcohol to produce CH3Cl and water.
Let's assume that the HCl is the limiting reagent.
We have 10ml of 12M , thus the total number of moles = concentration × volume = 10mL × 12 = 0.01L × 12 = 0.12moles.
If 1 moles of RCl = 1 mole of HCl.
Then, y g/mol of RCl = 1 mol of RCl.
Thus, we have y (gram/mol) of RCl.
Therefore, the theoretical yield = .12 moles × y g/mol. = 0.12y grams.
SUMMARY: The theoretical yield is calculated by Determination of the mass in gram of the product through the use of limiting reagent.
