The conversion of volume to moles at STP is 1 mole.
The ideal gas equation is given as :
P V = n R T
where,
P = pressure of the gas
V = volume of the gas
n = ?
R = constant = 0.823 atm L / mol K
T = temperature
At STP , the pressure is 1 atm and the temperature is 273.15 K, the volume At STP is 22.4 L.
moles , n = P V / R T
n = ( 1 × 22.4 ) / (0.0823 × 273.15)
n = 1 mole
Thus, at STP , the number of moles is 1 mol.
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Yes, but they are tubular organs and like all other organs are made up of tissues
Answer:
0.517
Explanation:
HCN + NaOH → NaCN + H2O [balanced as written]
(35.4 mL) x (0.268 M NaOH) x (1 mol HCN / 1 mol NaOH) / (18.35 mL HCN) = 0.517 M HCN
Answer:
39.6 mL
Explanation:
Step 1: Write the balanced neutralization reaction
Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)
Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH
The molar mass of CH₃COOH is 60.05 g/mol.
2.78 g × 1 mol/60.05 g = 0.0463 mol
Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH
The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.
Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂
0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL
