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Furkat [3]
4 years ago
12

The element lead (Pb) consists of four naturally occurring isotopes with atomic masses 203.97302,205.97444,206.97587, and 207.97

663 amu. The relative abundances of these four isotopes are 1.4,24.1,22.1, and 52.4 %, respectively. From these data, calculate the atomic weight of lead.
Chemistry
1 answer:
Sphinxa [80]4 years ago
4 0

Answer:

The atomic weight of lead is 207.2169 amu

Explanation:

Step 1: Data given

Lead has 4 isotopes:

⇒ 203.97302 = 1.4 %

⇒ 205.97444 = 24.1 %

⇒ 206.97587 = 22.1 %

⇒ 207.97663 = 52.4 %

Step 2: Calculate the atomic weight of lead

Atomic weight = 203.97302 * 0.014 + 205.97444*0.241 + 206.97587 *0.221 + 207.97663 * 0.524

Atomic weight = 207.21688371  ≈ 207.2169 amu

The atomic weight of lead is 207.2169 amu

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Answer:

The reaction between zinc and acetic acid is a single-replacement reaction. During this type of reaction basically one element replaces one compound.

The balanced equation for the reaction between zinc and acetic acid is

Zn(OH)_2 +2CH_3 COOH ----> Zn(CH_3COO)_2+2H 2O

Or this might help too!

Balanced Chemical Equation

A balanced chemical equation is defined as the chemical equation which has an equal number of atoms on both sides of the reaction arrow. A balanced chemical equation is based on the law of conservation of mass.

Answer and Explanation:

Below is the reaction between acetic acid and Zinc:  

Z n  +  2 H C 2 H 3 O 2  →  Z n ( C H 3 C O O ) 2  +  H 2

This reaction is an example of a reaction between an acid and a metal. When an acid reacts with a metal, salt, and Hydrogen gas forms. The Hydrogen gas formed here can be tested as it burns with a POP sound.

<h2>Hope this helps!!!</h2>
8 0
3 years ago
What is the density of 53.4 wt aqueous naoh?
zhenek [66]

Missing question: what is the density of 53.4 wt% aqueous NaOH if 16.7 mL of the solution diluted to 2.00L gives 0.169 M NaOH?

Answer is: density is 1.52 g/mL.

c₁(NaOH) = ?; molarity of concentrated sodium hydroxide.

V₁(NaOH) = 16.7 mL; volume of concentrated sodium hydroxide.

c₂(NaOH) = 0.169 M; molarity of diluted sodium hydroxide.

V₂(NaOH) = 2.00 L · 1000 mL/L = 2000 mL; volume of diluted sodium hydroxide.  

Use equation: c₁V₁  = c₂V₂.

c₁ = c₂V₂ / V₁.

c₁ = 0.169 M · 2000 mL / 16.7 mL.

c₁(NaOH) = 20.23 M.

m(NaOH) = 20.23 mol · 40 g/ml.

m(NaOH) = 809.53 g.

The mass fraction is the ratio of one substance (in this example sodium hydroxide) with mass to the mass of the total mixture (solution).

Make proportion: m(NaOH) : m(solution) = 53.4 g : 100 g.

m(solution) = 1516 g in one liter of solution.

d(solution) = 1516 g/L = 1.52 g/mL.

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3 years ago
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The answer would be two
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3 years ago
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Dennis_Churaev [7]

Answer:

(dont know if this is correct took this last year)

Explanation:

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6 0
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For a given substance, what links moles to moles?
ioda

Answer:

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Explanation:

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