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Natasha2012 [34]
3 years ago
5

An atom of lithium (Li) forms an ionic bond with an atom of chlorine (Cl) to form lithium chloride. How are the valence electron

s of these atoms rearranged to form this bond? A few valence electrons are shared between the atoms. Many valence electrons are shared between the atoms. Electrons are transferred from the chlorine atom to the lithium atom. Electrons are transferred from the lithium atom to the chlorine atom.
Chemistry
2 answers:
muminat3 years ago
6 0

Answer: Electrons are transferred from the lithium atom to the chlorine atom.

Explanation: Metal atoms tend to give away valence electrons when they bond with nonmetal atoms.

nalin [4]3 years ago
5 0

<u>Answer:</u> The correct statement is electrons are transferred from the lithium atom to the chlorine atom.

<u>Explanation:</u>

Ionic bond is defined as the bond which is formed from the complete transfer of electrons from one atom to another atom. The atom which looses electrons is known as electropositive atom and it attains positive charge. The atom which gains electrons is known as electronegative atom and it attains negative charge.

Lithium is the 3rd element of the periodic table. The electronic configuration of this element is 1s^22s^1

This element will loose 1 electron to attain stable electronic configuration to attain +1 oxidation state.

Chlorine is the 17th element of the periodic table. The electronic configuration of this element is 1s^22s^22p^63s^22p^3

This element requires 1 electron to attain stable electronic configuration to attain -1 oxidation state.

Hence, electrons are transferred from the lithium atom to the chlorine atom.

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Determine the amount of water that must be added to a 2-litre solution of sulphuric acid to dilute it from a pH of 2.7 to a pH o
Ksivusya [100]

Answer:

Volume of water added = 2.0 L

Explanation:

Initial pH of the solution = 2.7

[H^+] concentration in 2 L solution of sulfuric acid,

pH = -log[H^+]

[H^+] = 10^{-pH}\ M

[H^+] = 10^{-2.7} = 0.001995\ M = 0.002\ M

Final pH of the solution = 3

Final [H^+] concentration of sulfuric acid,

[H^+] = 10^{-pH}\ M

[H^+] = 10^{-3} = 0.001\ M

Now,

M_1V_1=M_2V_2

0.002 \times 2.0 = 0.001 \times V_2

V_2 = \frac{0.002 \times 2.0}{0.001} = 4.00\ L

Volume added = Final volume - Initial volume

                        = 4.0 - 2.0 = 2.0 L

4 0
3 years ago
The water molecule H2O is polar because it contains two polar single bonds and A. its molecule has a linear shape. B. molecules
Anni [7]
<span>c. it has a bent shape</span>
4 0
3 years ago
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What is the empirical formula of an oxide of nitrogen containing 63.61% by mass of nitrogen and 36.69% by mass of oxygen?
katen-ka-za [31]

Answer:

D. N₂O

Explanation:

Let's assume we have 100 g of the compound.  That means it consists of 63.61 grams of nitrogen and 36.69 grams of oxygen.

Converting masses to moles:

63.61 g N × (1 mol N / 14.01 g N) = 4.540 mol N

36.69 g O × (1 mol O / 16.00 g O) = 2.293 mol O

Normalize by dividing by the smallest:

4.540 / 2.293 = 1.980 mol N

2.293 / 2.293 = 1.000 mol O

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8 0
3 years ago
10. A small gold nugget has volume of 0.87 cm3. What is its mass if the density of gold is 19.3 g/cm3?
bulgar [2K]

Answer:

16.791 grams

Explanation:

The density formula is:

d=\frac{m}{v}

Rearrange the formula for m, the mass. Multiply both sides of the equation by v.

d*v=\frac{m}{v}*v

d*v=m

The mass of the gold nugget can be found by multiplying the density and volume. The density is 19.3 grams per cubic centimeter and the volume is 0.87 cubic centimeters.

d= 19.3 g/cm^3\\v-0.87 cm^3

Substitute the values into the formula.

m=d*v

m= 19.3 g/cm^3*0.87 cm^3

Multiply. Note that the cubic centimeters, or cm³ will cancel each other out.

m=19.3 g*0.87

m=16.791 g

The mass of the gold nugget is 16.791 grams.

8 0
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7 0
3 years ago
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