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Lerok [7]
3 years ago
11

The volume (V) of a cylinder can be found using the formula V = (pi)r^2h, where r is the radius and h is the height. A cylinder

has a diameter of
2 inches. It is filled with water to a the height of 4 inches. The water is then transferred to a new cylinder with a diameter of 4 inches.
What is the height of the water in the new cylinder?
Mathematics
1 answer:
andre [41]3 years ago
6 0

Answer:

1 inch

Step-by-step explanation:

volume of first cylinder = volume of  second cylinder because it never changes it stays the same

volume of first cylinder = (pi) (1)^2 (4) = 4pi

height of second cylinder: 4pi = (pi) (2)^2 h

pi would cancel so you are left with 4=4h

where height of second cylinder would be 1 in

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I need the domain range and function. With an explanation
erastovalidia [21]
<h3>Answers:</h3>

Problem 1

  • Domain = -3 < x \le 3, interval notation (-3, 3]
  • Range = -3 \le y < 3, interval notation [-3, 3)
  • Is it a function? Yes

Problem 2

  • Domain = x \ge -2, interval notation [-2, \infty)
  • Range = All real numbers, interval notation (-\infty, \infty)
  • Is it a function? No

Problem 3

  • Domain = -4 \le x < 3, interval notation [-4, 3)
  • Range = -4 < y \le 3, interval notation (-4, 3]
  • Is it a function? Yes

Problem 4

  • Domain = All real numbers, interval notation (-\infty, \infty)
  • Range = y \le 4, interval notation (-\infty, 4]
  • Is it a function? Yes

==================================================

Explanations:

  1. The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore -3 < x \le 3 which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
  2. The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is x \ge -2 which in interval notation is [-2, \infty). The range is (-\infty, \infty) to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
  3. This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
  4. This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is y \le 4 which is the same as saying (-\infty, 4] in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

7 0
4 years ago
I need help with number 9
ch4aika [34]

Answer:

D

Step-by-step explanation:

We can safely assume we are dealing with an arithmetic scale because the type of scale isn't mentioned anywhere. The more right a point is on the scale, the higher its value is. We are given two points of the scale: 3 and 4. Because the scale is arithmetic, we know that 3.8 must lie on 4/5s of the length between 3 and 4 to the right of 3, which is exactly where point D is.

3 0
3 years ago
I need help again...
Vadim26 [7]

the answer is 2 what you do to the bottom you do to the top

6 0
2 years ago
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Answer:

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Step-by-step explanation:

3 0
3 years ago
Solve –2x2 +3x – 9 = 0. (solving quadratic equation with complex numbers)..
goldfiish [28.3K]
-3+-sqrt9-56/-4
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4 0
3 years ago
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