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2 answers:
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Answer:
The heaviest 5% of fruits weigh more than 747.81 grams.
Step-by-step explanation:
We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.
Let X = <u><em>weights of the fruits</em></u>
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = population mean weight = 733 grams
= standard deviation = 9 grams
Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;
P(X > x) = 0.05 {where x is the required weight}
P( >
) = 0.05
P(Z > ) = 0.05
In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;
x = 747.81 grams
Hence, the heaviest 5% of fruits weigh more than 747.81 grams.
Answer:
The test statistics is
The p-value is
Step-by-step explanation:
From the question we are told
The West side sample size is
The number of residents on the West side with income below poverty level is
The East side sample size
The number of residents on the East side with income below poverty level is
The null hypothesis is
The alternative hypothesis is
Generally the sample proportion of West side is
=>
=>
Generally the sample proportion of West side is
=>
=>
Generally the pooled sample proportion is mathematically represented as
=>
=>
Generally the test statistics is mathematically represented as
=>
=>
Generally the p-value is mathematically represented as
From z-table
So