Write a rule for the linear function whose graph has slope m and contains the given point.
1 answer:
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Answer:
see the attached for a graph
the range is (-∞, 1] ∪ [1, ∞)
Step-by-step explanation:
You know the range of the sine function is [-1, 1], including zero. So, the minimum absolute value of 1/sin(x) will be 1/1 = 1, and it will go up from there (or down from -1) toward infinity. The vertical asymptotes will be where sin(x) = 0, at multiples of π.
To graph it by hand, you can pick a few points in any quadrant of the sine function and find their inverses. Plot those. You can take advantage of the symmetry about π/2 and about the origin. You can also take advantage of the periodicity.
A graph is attached.
Answer: B. t = 9.6tan(29°)
Step-by-step explanation:
<u>Based on the fact:</u>
<u>Set x = 29 and solve:</u>
The perimeter of the square is given by:
Where,
x: square side.
Substituting values we have:
Rewriting the perimeter of the square we have:
Finally, dividing both values:
Answer:
the perimeter of the square is: