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3 years ago

9

Plz help me really really fast this is my last question to work on

1 answer:

Artyom0805 [142]3 years ago

6 0

Answer:

$5

Step-by-step explanation:

25 = 4e + 5

20 = 4e

5 = e

reach eraser costs $5.

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Please please use explanation with answer

KIM [24]

Answer:

$\large\boxed{\theta=-\dfrac{\pi}{4}+k\pi\ or\ \theta=k\pi}\ for\ k\in\mathbb{Z}$

Step-by-step explanation:

$\tan^2\theta+\tan\theta=0\\\\\tan\theta(\tan\theta+1)=0\iff\tan\theta=0\ \vee\ \tan\theta+1=0\\\\\tan\theta=0\Rightarrow \theta=k\pi\ \text{for}\ k\in\mathbb{Z}\\\\\tan\theta+1=0\qquad\text{subtract 1 from both sides}\\\\\tan\theta=-1\Rightarrow\theta=-\dfrac{\pi}{4}+k\pi\ \text{for}\ k\in\mathbb{Z}$

5 0

3 years ago

1/8 divided by 2/7=?

Sliva [168]

1/112 or 0.008929 hope that helps

7 0

3 years ago

Read 2 more answers

Does -2(z+3)-z=-z-4(z+2) have one,zero or infinite solutions

Andrew [12]

Hello from MrBillDoesMath!

Answer:

One solution (z = -1)

Discussion:

-2(z+3)-z=-z-4(z+2) =>

-2z -6 -z = -z -4z - 8 =>

-3z -6 = -5z -8 => add 6 to both sides

-2z = -5z -2 => add 5z to both sides

3z = -5z +5z -3 =>

3z = -3 =>

z = -1

Thank you,

MrB

6 0

3 years ago

Your bank account is sitting on $14,000. You started with a principal balance of $12,500. If the interest rate was 4.5% compound

Simora [160]

Answer:

$t=2.5\ years$

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\ P=\$12,500\\P=\$14,000\\ r=4.5\%=4.5/100=0.045$

substitute in the formula above and solve for t

$14,000=12,500(e)^{0.045t}$

Simplify

$14,000/12,500=(e)^{0.045t}$

$1.12=(e)^{0.045t}$

Apply ln both sides

$ln(1.12)=ln[(e)^{0.045t}]$

$ln(1.12)=(0.045t)ln(e)$

Remember that

$ln(e)=1$

so

$ln(1.12)=(0.045t)$

$t=ln(1.12)/(0.045)$

$t=2.5\ years$

3 0

3 years ago

What is the equation of the line in standard form of the graph below?

Mashcka [7]

Answer:

Step-by-step explanation:

8 0

2 years ago