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Zigmanuir [339]
3 years ago
13

Need help due in 10!

Mathematics
1 answer:
lakkis [162]3 years ago
8 0

Answer:

1. (28-2)x

2.(12+6)x

3.(15+1)x

Step-by-step explanation:

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Find the arc length of a central angle of pi/6 in a circle whose radius is 10 inches.
gogolik [260]

Answer:

= 5/3 * pi  inches

  or approximately 5.235987756 inches

Step-by-step explanation:

The formula for arc length = r * theta  where theta is in radians

arc length = 10 * pi/6

                 = 10/6 * pi

                = 5/3 * pi

                or approximately 5.235987756 inches

8 0
3 years ago
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The radius of a circle is 1 foot. What is the length of a 45 degree arc
Elodia [21]
Circumference = 2 x PI x r
circumference = 3.14 x 2 x 12 inches = 75.36 inches

45/360 = 0.125

75.36 * 0.125 = 9.42 inches
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3 years ago
There are 430 people in a wave pool. Write an inequality that represents how many more people p can enter the pool.
san4es73 [151]
1x=430 people .........
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3 years ago
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
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The area of a square rug is 169ft^2. How long is each side of the rug?
jek_recluse [69]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{13 \: ft}}}}}

Step-by-step explanation:

\star{ \sf{ \: Area \: of \: a \: square \: rug \: ( \: A \: ) \:  =  \: 169 \:  {ft}^{2} }}

\sf{ \underline{Finding \: the \: length \: of \: a \: square \: ( \: l \: )}}

\boxed{ \sf{Area \: of \: a \: square \:  =  \:  {l}^{2} }}

\hookrightarrow{ \sf{169 =  {l}^{2} }}

\hookrightarrow{ \sf{ {l}^{2}  = 169}}

\hookrightarrow{ \sf{ \sqrt{ {(l)}^{2} }  =  \sqrt{169} }}

\hookrightarrow{ \text{length \:  =  \: 13 \: ft}}

\text{Hope \: I \: helped!}

\text{Best \: wishes !!}

~\text{TheAnimeGirl}

6 0
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