mason used 1/6 of a gram of honey to make 1/12 of a pan of pudding. how many grams of honey are needed to make a full pan of pud

Question

RSB [31]

3 years ago

7

mason used 1/6 of a gram of honey to make 1/12 of a pan of pudding. how many grams of honey are needed to make a full pan of pud

ding? please leave work below!

Mathematics

2 answers:

antiseptic1488 [7] · Answer 1 · 2022-01-21T15:59:18+03:00

Answer:

I believe it"s 2 grams

Step-by-step explanation:

Given,

Quantity of honey required for part of pudding = grams,

Since, total part of pudding = 1,

The number of parts in the pudding = 12,

So, the number of gram of honey needed for 1 full part of pudding = number of parts × honey required for part,

= 12 × × \frac{1}{6}

= \frac{12}{6}

=

= 2

Dima020 [189] · Answer 2 · 2022-01-21T14:07:01+03:00

Answer:

2 grams

Step-by-step explanation:

1/12 goes into 1 (representing a full pan) 12 times. This means that 12 spoons of the 1/6 grams are needed to make a full pan of pudding. So, you multiply 12 by 1/6, and that results in 2 grams. You need to have 2 grams of honey to make a full pan of pudding.