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RSB [31]
4 years ago
7

mason used 1/6 of a gram of honey to make 1/12 of a pan of pudding. how many grams of honey are needed to make a full pan of pud

ding? please leave work below!
Mathematics
2 answers:
antiseptic1488 [7]4 years ago
6 0

Answer:

I believe it"s 2 grams

Step-by-step explanation:

Given,

Quantity of honey required for  part of pudding =  grams,

Since, total part of pudding = 1,

The number of  parts in the pudding = 12,

So, the number of gram of honey needed for 1 full part of pudding = number of  parts × honey required for  part,

= 12 × × \frac{1}{6}

= \frac{12}{6}

=

= 2

Dima020 [189]4 years ago
5 0

Answer:

2 grams

Step-by-step explanation:

1/12 goes into 1 (representing a full pan) 12 times. This means that 12 spoons of the 1/6 grams are needed to make a full pan of pudding. So, you multiply 12 by 1/6, and that results in 2 grams. You need to have 2 grams of honey to make a full pan of pudding.

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We can quickly get a temporary value for x by altering the original equation.

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Now that we know the exact value of y, we can plug it back into the original equation.

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