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3 years ago

Which box plot correctly represents the data 1,1,5,5,7,8,8,10,12

Mathematics

1 answer:

lyudmila [28]3 years ago

8 0

Answer: A I think

Step-by-step explanation: Taking the test rn

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Solve (x - 3)² = 5 Give your solutions correct to 3 significant figures.

zvonat [6]

Answer:

$\sqrt{5} +3, -\sqrt{5} + 3$ or 5.236, 0.764

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Suma a 3 numere naturale este 163. Scazand al treilea numar din suma primelor doua numere, obtinem 67. Scazand primul numar din

Vika [28.1K]

Answer: x=63, y=52, z=48

Step-by-step explanation:

The complete question in english is:

The sum of 3 natural numbers is 163. By subtracting the third number from the sum of the first two numbers, we get 67. By subtracting the first number from the sum of the last 2 numbers, we get 37. Determine the 3 numbers

According to this we have a system with three equations and three unknown values:

$x+y+z=163$ (1)

$x+y-z=67$ (2)

$-x+y+z=37$ (3)

Let's begin by isolating $x$ from (1):

$x=163-y-z$ (4)

And substitute (4) in (2):

$163-y-z+y-z=67$ (5)

Isolating $z$ :

$z=48$ (6) We have found the first number

Substituting (6) in (1):

$x+y+48=163$ (7)

Adding (7) to (3):

$\left \{ {{x+y+48=163} \atop {-x+y+z=37}} \right$

We have the following:

$2y+96=200$

Isolating $y$ :

$y=52$ (8) This is the second number

Substituting (6) and (8) in (1):

$x+52+48=163$ (9)

Isolating $x$ :

$x=63$ (10) This is the third number

8 0

4 years ago

Nts) in a certain population of voters, 72% of them plan to vote in favor of a new

Ganezh [65]

Answer:

Probability that 10 of them plan to vote against this piece of proposed legislation is 0.0701 or 7.01 %.

Step-by-step explanation:

Consider the event of voting against the piece as success, 'p'. So, voting in favor of the piece is failure and denoted by 'q'.

Given:

Sample size is, $n=25$

Probability of failure is, $q=72\%=0.72$

Therefore, probability of success is, $p=1-q=1-0.72=0.28$

Number of successes is, $x=10$

Now, from Bernoulli's distribution, probability of $x$ successes out of $n$ samples is given as:

$P(X=x)=_{n}^{x}\textrm{C}p^xq^{n-x}$

Here, $n=25,x=10,p=0.28,q=0.72$ . Therefore,

$P(X=10)=_{25}^{10}\textrm{C}(0.28)^{10}(0.72)^{25-10}\\P(X=10)=_{25}^{10}\textrm{C}(0.28)^{10}(0.72)^{15}\\P(X=10)=3.269\times 10^{6}\times 2.962\times 10^{-6}\times 7.244\times 10^{-3}\\P(X=10)=70.142\times 10^{-3}=0.0701=7.01\%$