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9966 [12]
3 years ago
13

Which box plot correctly represents the data 1,1,5,5,7,8,8,10,12

Mathematics
1 answer:
lyudmila [28]3 years ago
8 0

Answer: A I think

Step-by-step explanation: Taking the test rn

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At the local animal shelter, there are 35 cats and 42 dogs. What is the ratio of dogs to cats at the local animal shelter?
postnew [5]

9514 1404 393

Answer:

  6 : 5

Step-by-step explanation:

The ratio is ...

  dogs : cats = 42 : 35 = (7·6) : (7·5) = 6 : 5

The ratio of dogs to cats at the shelter is 6 to 5.

6 0
3 years ago
Some helppppp!!!!! I’m having trouble
USPshnik [31]
Answer:

1.4*40=56cm, DVD’s he has

1.4*3=4.2cm

56+4.2=60.2cm, whoops too much. So instead 1.4*2= 2.8cm, 56+2.8=58.8cm Is Your Answer.
3 0
3 years ago
Read 2 more answers
Evaluate the limit assuming that limx→−5f(x)=17limx→−5f(x)=17 and limx→−5g(x)=22limx→−5g(x)=22. (use symbolic notation and fract
Gemiola [76]

In this question it is given that

\lim_{x->-5}f(x)=17, \lim_{x->-5}g(x)=22

And we have to find the value of the given limit

\lim_{x->-5}(23f(x)+3g(x))

Using properties of limit, first we separate the two functions, that is

23\lim_{x->-5}f(x)+3\lim_{x->-5}g(x)

Substituting the values of the given limit,

23(17)+3(22)=457

3 0
3 years ago
Sas a ribbon that is 5/6 yard long. She cuts off 3/5 of that ribbon and uses it to tie her hair back. She gives the rest to her
Ivenika [448]

Answer:

7/30

Step-by-step explanation:

5/6 = 25/30  3/5 = 18/30

25/30 - 18/30 = 7/30

Sas gives 7/30 of the ribbon to her sister.

Hope this helps! :3

5 0
3 years ago
Suppose that we have two identical boxes: box 1 and box 2. box 1 contains 5 red balls and 3 blue balls. box 2 contains 2 red bal
sineoko [7]

(a) The probability of drawing a blue marble at random from a given box is the number of blue marbles divided by the total number of marbles. We assume that the probability of selecting one of two boxes at random is 1/2 for each box.

... P(blue) = P(blue | box1)·P(box1) + P(blue | box2)·P(box2) = (3/8)·(1/2) + (4/6)·(1/2)

... P(blue) = 25/48 . . . . probability the ball is blue

(b) P(box1 | blue) = P(blue & box1)/P(blue) = (P(blue | box1)·P(box1)/P(blue)

... = ((3/8)·(1/2))/(25/48)

... P(box1 | blue) = 9/25 . . . . probability a blue ball is from box 1

8 0
3 years ago
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