[ ( x + 4 )( x + 5 ) + 4( x + 1 )( x + 5) - 5( x + 1 )( x + 4 ) ] / [( x + 1 )( x + 4)( x + 5 )] = ( x^2 + 9x + 20 + 4x^2 + 24x +20 - 5x^2 - 25x - 20) / [( x + 1 )( x + 4)( x + 5 )] =
( - 2x + 20 ) / [( x + 1 )( x + 4)( x + 5 )] = ( - 2)( x - 10) / [( x + 1 )( x + 4)( x + 5 )]
The customer can purchase 1.19788 pounds of cheese (approximately 1.2 pounds).
<h3>
How much cheese can she purchase?</h3>
We are given with the cost of ham is $2.49 per pound and
Cost of swiss cheese is $3.79 per pound.
So, the cost of 2 pounds of ham will be given as-
= 2× $2.49
= $4.98
Since, the customer has a total of $9.50 to spend on 2 pounds of ham and some cheese,
∴ Let the number of pounds of cheese she can purchase be x.
Then the equation will be this:
2.49*2 + 3.79*x = 9.50
4.98 + 3.79x = 9.50
Subtracting 4.98 from each side we get-
4.98 -4.98 + 3.79x = 9.50-4.98
3.79x = 4.54
x
x = 1.19788 pounds of cheese (approximately 1.2 pounds).
Hence, the customer can purchase 1.19788 pounds of cheese (approximately 1.2 pounds).
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Answer: rate of train A = 120 km/h
rate of train B = 101 km/h
Step-by-step explanation:
Let x = the speed of train A
Let y = the speed of train B
One train travels 19 km/h slower than the other. Let train B be the slower train. Therefore,
x = y + 19 - - - - - - - - - -1
Recall
Speed = distance/time
Distance = speed × time
If they meet in 3 hours, it means that train A has travelled a distance of
x × 3 = 3x km
And train B has travelled a distance of y × 3 = 3y km
Train A and Train B were 663 kilometers apart when they left their respective destinations. They left at the same time and travelled towards each other. This means that if they meet in 3hours time, they must have covered a total of 663 km. Therefore,
3x + 3y = 663 - - - - - - - - - 2
Substituting x = y + 19 into equation 2, it becomes
3(y + 19) + 3y = 663
3y + 57 + 3y = 663
6y + 57 = 663
6y = 663 - 57 = 606
y = 606/6 = 101 km/h
x = y + 19 = 101 + 19
x = 120 km/h
Answer:
27%
Step-by-step explanation:
6/10*45/100=270/1000 which is 27/100 which is 27%