How to translate words into equations
1 answer:
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Sets and set operations are ways of organizing, classifying and obtaining information about objects according to the characteristics they possess, as objects generally have several characteristics, the same object can belong to several sets, an example is the subjects of a school , where students (objects) are classified according to the subject they study (set).
The <em>intersection</em> of sets is a new set consisting of those objects that simultaneously possess the characteristics of each intersected set, the intersection of two subjects will be those students who have both subjects enrolled.
The <em>union</em> of sets is a new set consisting of all the objects belonging to the united sets, the union of two subjects will be all students of both courses.
In this case there are three sets B, C and S of which we are given the following information:
Answer
n(BꓵSꓵC)=5
n(BꓵS)=10 – 5 = 5
n(BꓵC)=12 – 5 = 7
n[(BꓵC)ꓴ(BꓵS)ꓴ(CꓵS)]=21 – 5 – 5 – 7 = 4
n(B)=36 – 5 – 5 – 7 = 19
n(S)=30 – 5 – 5 – 4 = 16
n(C)=34 – 5 – 7 – 4 = 18
Answer:
- The interval [9, 10] is 1,375% greater than the interval [5, 8].
- The interval [9, 10] is 14.75 times greater than the interval [5, 8].
Step-by-step explanation:
1. To solve this problem you must apply the following formula:
2. Let's calculate the average rate of change of each interval:
a) Interval [9,10]:
b) Interval [5,8]:
3. The difference is:
4. In percentage:
5. You have that the interval [9,10] is 14.75 times greater than the interval [5,8], as you can see below: