solve y 6.3=0.9y thats all the question i dont understand it so thats why im trying to get the answer to the problem
1 answer:
What it wants you to do is to put it into a form where on the one side of the equation there is y and nothing else. for this, we need to get rid of the 0.9.
how do we do that?
we divide both sides of the equation by 0.9:
6.3/0.9=y
that's ugly, right? but if both denominator and nominator are decimal fractions of the same sort; we can multiply both by 10 and get rid of the point:
63/09=y
and...
so basically 7=y, or y=7
and this is the solution!
how do we do that?
we divide both sides of the equation by 0.9:
6.3/0.9=y
that's ugly, right? but if both denominator and nominator are decimal fractions of the same sort; we can multiply both by 10 and get rid of the point:
63/09=y
and...
so basically 7=y, or y=7
and this is the solution!
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Answer:
a) 26.33 kg/d and 29.67 kg/d
b) 94.5%
Step-by-step explanation:
a. Find a 99% confidence interval for the true mean milk production.
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 28 - 1.67 = 26.33 kg/d
The upper end of the interval is the sample mean added to M. So it is 28 + 1.67 = 29.67 kg/d
The 99% confidence interval for the true mean milk production is between 26.33 kg/d and 29.67 kg/d
b. If the farms want the confidence interval to be no wider than ± 1.25 kg/d, what level of confidence would they need to use?
We need to find z initially, when M = 1.25.
When , it has a pvalue of 0.9725.
1 - 2*(1 - 0.9725) = 0.945
So we should use a confidence level of 94.5%.