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3 years ago

Paul is making grey paint.

1 answer:

5 0

Its quite simple. for every white bucket of paint he uses, he uses 3 buckets of black paint as well. so if he made 24 litres of grey paint then he would have had to use 24 buckets of white paint. but, this might be a trick question because its saying he made 24 "litres" but the unit it started with was "buckets" so it might be trying to trick you because we dont know how much paint is in one "bucket"

You might be interested in

Use the grouping method to factor this polynomial completely.<br> 483 + 8x2 + 3x + 6

densk [106]

Answer:

(4x² +3)(x +2)

Step-by-step explanation:

4x³ +8x² +3x +6 = (4x³ +8x²) +(3x +6)

= 4x²(x +2) +3(x +2)

= (4x² +3)(x +2)

We assume you want real integers in the factors. Further factoring gets into complex irrational factors.

(2x -i√3)(2x +i√3)(x +2)

5 0

3 years ago

1 point

SpyIntel [72]

Answer:

1600

Step-by-step explanation:

1200 = 75%

1200 ÷ 3 = 25% = 400

400 x 4 = 1600

6 0

3 years ago

Permutations vs combinations(one step):

Bogdan [553]

Answer:

the expression is: $^{15}P_3=\frac{15!}{(15-3)!}$

and 2730 different ways are possible.

Step-by-step explanation:

In the given question we have to choose a president, vice

president, and secretary.

Permutations are used when order is important so, as in the given question order is required. We would use permutations

The formula used is: $^nP_r=\frac{n!}{(n-r)!}$ where:

n=total number of objects

r=number of objects selected

In our case: n=15, r=3

Putting values and finding the answer:

$^nP_r\\^{15}P_3=\frac{15!}{(15-3)!} =2730 \ ways$

So, the expression is: $^{15}P_3=\frac{15!}{(15-3)!}$

and 2730 different ways are possible.

7 0

3 years ago

HELP PLEASE ! TRUE OR FALSE ?!

miss Akunina [59]

This is false because on 2) x does not equal 3.

8 0

3 years ago

A = ???? 4 −2

irinina [24]

Answer:

1. The matrix A isn't the inverse of matrix B.

2. |B|=12, |A|=12

Step-by-step explanation:

1. We want to know if matrix A is the inverse of matrix B, this means that if you do the product between B and A you have to obtain the identity matrix.

We have:

$A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]$

and

$B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]$

A and B are 2×2 matrices (2 rows and 2 columns), if you multiply them you have to obtain a 2×2 matrix.

Then if A is the inverse of B:

$B.A=I$

Where,

$I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

Observation:

If you have two matrices:

$A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A.B=\left[\begin{array}{cc}(a.e+b.g)&(a.f+b.h)\\(c.e+d.g)&(c.f+d.h)\end{array}\right]$

Now:

$B.A=\left[\begin{array}{cc}3&2\\1&4\end{array}\right].\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}4.3+(-2).1&4.2+(-2).4\\(-1).3+3.1&(-1).2+3.4\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}12-2&8-8\\-3+3&-2+12\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]$