Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.
Hope I could help.
A parallelogram with congruent diagonals is a
.. B - rectangle.
Blaise Pascal (June 19, 1623 - August 19, 1662) was a great contributor to math, science, and philosophy, especially Christian philosophy. Interesting Blaise Pascal Facts: Pascal's early education in France was conducted at home by his father due to the prodigious talent and understanding he showed as a child. Did u mean pascal instead of pasical becaus ethere is no such thing. Hope I helped :)
Answer:
The simplest form is tan(4x)
Step-by-step explanation:
* Lets revise the identity of the compound angles
- 
- 
* Lets solve the problem
- Let 9x = 5x + 4x
∴ tan(9x) = tan(5x + 4x)
- Use the rule of the compound angle
∵ 
⇒ (1)
∵ 
⇒ (2)
∵ tan(9x) = equation (2)
- Substitute (2) in (1)
∴ 
- Multiply up and down by (1 - tan(5x)tan(4x))
∴ ![\frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}](https://tex.z-dn.net/?f=%5Cfrac%7Btan%285x%29%2Btan%284x%29-tan%285x%29%5B1-tan%285x%29tan%284x%29%5D%7D%7B1-tan%285x%29tan%284x%29%2Btan%285x%29%5Btan%285x%29%2Btan%284x%29%5D%7D)
- Simplify up and down
∴ 
∴ ![\frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}](https://tex.z-dn.net/?f=%5Cfrac%7Btan%284x%29%2Btan%5E%7B2%7D%285x%29tan%284x%29%7D%7B%5B1%2Btan%5E%7B2%7D%285x%29%5D%7D)
- Take tan(4x) as a common factor up
∴ ![\frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}](https://tex.z-dn.net/?f=%5Cfrac%7Btan%284x%29%5B1%2Btan%5E%7B2%7D%285x%29%5D%7D%7B%5B1%2Btan%5E%7B2%7D%285x%29%5D%7D)
- Cancel [1 + tan²(5x)] up and down
∴ The answer is tan(4x)
