Hey there!
Let's first find an easier situation.
If we're saying:
How many fives are in ten?
We're doing 10 divided by 5, because we're seeing how many 5's go into 10.
It's no different here.
We will be doing 6 divided by 3/4, just as we did with our simpler situation.
Using our "keep, switch, flip" rule (keep first term, change to multiplication, take reciprocal of second term)
we get:
6 divided by 3/4
=
6 * 4/3
= 24/3
= 8 3/4's in 6.
Hope this helps!
Answer:
correct
Step-by-step explanation:
supplementary is when 2 angles add up to 180
Start by decomposing the number inside the root into primes
Then group the terms into cubes if possible

rewrite the root
![\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D%5Csqrt%5B3%5D%7B10%5Ccdot2%5E3%7D)
then cancel the terms that are cubes and bring them out of the root
Answer:
x=3
z=65
Step-by-step explanation:
6x+97 and 14x+73 are vertical angles which means they are equal
6x+97= 14x+73
Subtract 6x from each side
6x-6x+97= 14x-6x+73
97 = 8x +73
Subtract 73 from each side
97-73 = 8x+73-73
24 = 8x
Divide each side by 8
24/8 = 8x/8
3 = x
Now we need to find z
6x+97 and z are supplementary angles which means they add to 180
6x+97 +z = 180
6(3) +97 +z = 180
18+97+z=180
Combine like terms
115+z = 180
Subtract 115 from each side
115-115 +z=180-115
z = 65