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4 years ago

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A surveyor is studying a map of the community and is using vectors to determine the distance between two schools. On the map, th

e surveyor determined that school A is at (7, 12), and school B is at (–21, –13). The scale of the map is 1 unit = 100 meters.
Which vector represents the path from school A to school B, and what is the actual distance between them?

A. components: actual distance: about 37.54 meters

B. components: , actual distance: about 3,754 meters

C. components: , actual distance: about 37.54 meters

D. components: , actual distance: about 3,754 meters

2 answers:

Gnoma [55]4 years ago

8 0

Answer:

The answer is C

Step-by-step explanation:

Just took the exam on EDG 2021

user100 [1]4 years ago

5 0

Answer:

Option C

Step-by-step explanation:

From the question we are told that

Co-ordinate of school A =(7,12)

Co-ordinate of school B =(-21,-13)

Generally the sum of the vector is mathematically represented

$(A+B)=(-21-7,-13-12)$

$(A+B)=(-28,-25)$

Generally the actual distance between the schools is mathematically given as

$d=\sqrt{-28^2+-25^2}$

$d=\sqrt{1409}$

$d=37.5366 \approx 37.537m$

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This series is convergent. The partial sums of this series converge to $\displaystyle \frac{2}{3}$ .

Step-by-step explanation:

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In this question, the $n$ th term of this original series is:

$\displaystyle a_{n} = \frac{{(-1)}^{n+1}}{{2}^{n}}$ .

The first thing to notice is the ${(-1)}^{n+1}$ in the expression for the $n$ th term of this series. Because of this expression, signs of consecutive terms of this series would alternate between positive and negative. This series is considered an alternating series.

One useful property of alternating series is that it would be relatively easy to find out if the series is convergent (in other words, whether $\displaystyle \lim\limits_{n \to \infty} S_{n}$ exists.)

If $\lbrace a_n \rbrace$ is an alternating series (signs of consecutive terms alternate,) it would be convergent (that is: the partial sum limit $\displaystyle \lim\limits_{n \to \infty} S_{n}$ exists) as long as $\lim\limits_{n \to \infty} |a_{n}| = 0$ .

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$\begin{aligned}\lim\limits_{n \to \infty} |a_n| &= \lim\limits_{n \to \infty} \left|\frac{{(-1)}^{n+1}}{{2}^{n}}\right| = \lim\limits_{n \to \infty} {\left(\frac{1}{2}\right)}^{n} =0\end{aligned}$ .

Therefore, this series is indeed convergent. However, this conclusion doesn't give the exact value of $\displaystyle \lim\limits_{n \to \infty} S_{n}$ . The exact value of that limit needs to be found in other ways.

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$\begin{aligned}S_n &= \frac{a_0 \cdot \left(1 - r^{n}\right)}{1 - r} \\ &= \frac{\displaystyle (-1) \cdot \left(1 - {(-1 / 2)}^{n}\right)}{1 - (-1/2)} \\ &= \frac{-1 + {(-1 / 2)}^{n}}{3/2} = -\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\end{aligned}$ .

Evaluate the limit $\displaystyle \lim\limits_{n \to \infty} S_{n}$ :

$\begin{aligned} \lim\limits_{n \to \infty} S_{n} &= \lim\limits_{n \to \infty} \left(-\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\right) \\ &= -\frac{2}{3} + \frac{2}{3} \cdot \underbrace{\lim\limits_{n \to \infty} \left[{\left(-\frac{1}{2}\right)}^{n} \right] }_{0}= -\frac{2}{3}\end{aligned}}_$ .

Therefore, the partial sum of this series converges to $\displaystyle \left(- \frac{2}{3}\right)$ .

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