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2 years ago

Inter quartile range is

1 answer:

5 0

A measure of variability, based on dividing a data set into quartiles. Quartiles divide a rank-ordered data set into four equal parts. The values that divide each part are called the first, second, and third quartiles; and they are denoted by Q1, Q2, and Q3, respectively.

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What is the result when −2/3 subtracted from −14/15?

disa [49]

Step-by-step explanation:

14/15 - 2/3 =

14/15 and 2/3 lcm is 15

so 14/15 becomes 14/15

- 2/3 become 10/15

15÷5=3 and 10÷5=2

so 14/15

-10/15=4/15

14-10 = 4

answer is 4/15 and since 15 can't be divided by 4 equally it is in simplest form at 4/15

7 0

2 years ago

Please Help!! Write the function I'm vertex form y = -x^2-2x+6 y=

balu736 [363]

Rewrite in standard form and use the form to find the vertex.

(1, 5)

(x - 1)^2 + 5

7 0

3 years ago

GIVING BRAINLIEST PLS HELP

AveGali [126]

Answer:

f(x) = x

Step-by-step explanation:

note : slope is positive 1, so the x term must be positive

also note the graph intersects the curve at y = 0, which means that they y-intercept is zero .

if we substitute this into the general equation for a line

y = mx + b, where m = +1 and b = 0,

we get y = x

or f(x) = x (in function form)

5 0

2 years ago

What is the solution to log 5 (x+30)= 3

Free_Kalibri [48]

Answer:

x = 95

Step-by-step explanation:

Using the rule of logarithms

• $log_{b}$ x = n ⇔ x = $b^{n}$

Given

$log_{5}$ (x + 30) = 3, then

x + 30 = 5³ = 125 ( subtract 30 from both sides )

x = 95

7 0

3 years ago

PLEASE HELP!!

PSYCHO15rus [73]

Answer:

The bird is approximately 9 ft high up in the tree

Explanation:

The required diagram is shown in the attached image

Note that the tree, the cat and the ground form a right-angled triangle

Therefore, we can apply special trigonometric functions

These functions are as follows:

$sin(\alpha)=\frac{opposite}{hypotenuse} \\ \\ cos(\alpha)=\frac{adjacent}{hypotenuse} \\ \\tan(\alpha)=\frac{opposite}{adjacent}$

Now, taking a look at our diagram, we can note the following:

α = 25°

The opposite side is the required height (x)

The adjacent side is the distance between the cat and the tree = 20 ft

Therefore, we can use the tan function

This is done as follows:

$tan(\alpha)=\frac{opposite}{adjacent}\\ \\ tan(25)=\frac{x}{20}\\ \\x=20tan(25) = 9. 32 ft$ which is 9 ft approximated to the nearest ft

Hope this helps :)

5 0

3 years ago