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GrogVix [38]
3 years ago
9

Someone please help me

Mathematics
1 answer:
Stella [2.4K]3 years ago
6 0

Answer:

-2/3

Step-by-step explanation:

Slope means steepness which means the gradient.

The formula for the gradient is the change in y / the change in x

The change in y is 7-3 which is 4

The change in x is -6 -0 which is -6

So we put 4/-6 which equals to -2/3

So the answer is -2/3.

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George earns $455 per week. George recieves a 20% raise. How can george calculate his new weekly per rate?
lara [203]
There are two ways to calculate his new pay. Choose whichever is easier for you.

OPTION 1:
multiply current pay by 20%, then add the result to the current pay

Step 1:
multiply pay by 20% increase
=$455 * 20%
=$91 increase

Step 2:
add pay increase from step 1 to current pay rate

=$455 + $91
=$546 new weekly rate


OPTION 2:
multiply current pay by (1 + 20%)

=($455)(1 + 20%)
=(455)(1.20)
=$546 new weekly rate


ANSWER: His new weekly rate is $546 per week.

Hope this helps! :)
4 0
3 years ago
The function is defined by ()= −2+6. What is the value of (10)?
kirill115 [55]

Answer:

x

Step-by-step explanation:

4 0
3 years ago
A cheetah runs at 65 miles per hour. Which equation represents his speed if y is the
Masteriza [31]

Answer:

c. y = 65x

Step-by-step explanation:

y = miles

x = hours

7 0
3 years ago
-8x+54x+140 where x is the number of $1 increases in prices
Alenkinab [10]
(-8×1)+(54×1)+140=186
8 0
3 years ago
The number of violent crimes committed in a day possesses a distribution with a mean of 2.2 crimes per day and a standard deviat
VARVARA [1.3K]

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

Step-by-step explanation:

For this case we have the following info given:

\mu = 2.2 represent the mean

\sigma = 6 represent the deviation

We select a sample size of n=100. This sample is >30 so then we can use the central limit theorem. And we want to find the distribution for the sample mean and we know that the distribution is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

6 0
4 years ago
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