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lakkis [162]
3 years ago
9

1. Each student at a school has a student identification number. Counselors have a computer

Mathematics
1 answer:
KatRina [158]3 years ago
3 0

Answer:

Simple random sampling

Step-by-step explanation:

From the sampling description explained above, the sampling method used is a simple random sampling method whereby a small subset or group is chosen from a larger set or population with all individuals in the population having exactly equal chance. The entire sample during a simple random sampling does not have to partitioned or subdivided into groups or subgroups. All individual samples are entirely sampled together with all having the sample probability of being chosen. This way the samples are representative of the entire population. All students in the scenario were sampled with any subdivision. Hence, we have a simple random sampling method.

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Someone plz help fast will give brainiest
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Answer:

$5

Step-by-step explanation:

The bill was $15 extra this month so 15 divided by 3 is 5.

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4 years ago
7. Reesa's sister is a salesperson at Old Navy.
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Answer: 24$

Step-by-step explanation:

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3 years ago
Express the partial sums ( sn) of the following geometric series recursively (Remember all three parts): 3 + 6 + 12 + 24 + ...
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The mean IQ score of students in a particular calculus class is 110, with a standard deviation of 5. Use the Empirical Rule to f
Anika [276]

Answer:

2.5%

Step-by-step explanation:

If the data set has a bell-shaped distribution, then you can use 68-95-99.7, or Empirical, rule. With bell-shaped distributions, 68% of results lie within 1 standard deviation of the mean, 95% of results lie within 2 standard deviations, and 99.7% lie within 3 standard deviations.

Your mean is 110, and you have a standard deviation of 5. This means that 68% of all students fall between IQ scores of 105 (110 - 5) and 115 (110 + 5), one standard deviation from the mean. To get 95% of the students, you need to go one more standard deviation out, so then you have 100 (105 - 5) and 120 (115 + 5), two standard deviations from the mean. 99.7% of the students fall between 95 (100 - 5) and 125 (120 + 5). What you want is to find the percentage of students with an IQ above 120.

The way I'd handle this is starting with what I know is absolutely, without a doubt, below 120. If you drew a quick bell curve to represent this data, everything to the left of the mean, 110, could be counted out right away (I usually color in half of the bell curve because I like the visual representation). Just like that, 50% of your data is gone. From there, I know 120 is right at 2 standard deviations away, so I color in all the way up to the 95% mark, but remember that when we took away 50%, you don't want to count all the standard deviations on the left side of the bell curve twice. So instead, take the 95% and cut it in half, which is 47.5%. Alternatively, you can start at 50% and count up 1 standard deviation (34%), and up one more (13.5%) and get the same result, 47.5%. So now you know 50 + 47.5 = 97.5% of results are LOWER than 120. To figure out what's higher than 120, all you have to do is see that

100% - 50% - 47.5% = 2.5%

And then you can see that 2.5% of students have an IQ over 120.

5 0
3 years ago
Solve the simultaneous equations<br> y = 4x + 1<br> y = 2x^2+ 7x - 1
mixer [17]

Answer:

Given,\\y = 4x+1......(1)\\y = 2x^2+7x-1.............(2)\\Equating~equation (1)~and~(2),\\4x+1 = 2x^{2} +7x-1\\or, 2x^{2}+7x-4x-1-1=0\\or, 2x^{2} + 3x-2=0\\or, 2x^{2} +4x-x-2=0\\or, 2x(x+2)-1(x+2)=0\\or, (x+2)(2x-1)=0\\i.e. x=-2 ~or~ \frac{1}{2} \\When~x=2,~equation(1)~becomes ~y=4(-2) +1=-7\\When~x=-\frac{1}{2},~equation (1)~becomes~y=4(\frac{1}{2}) +1 = 2+1=3

So, the required values of x are -2 and 1/2 and that of y are -7 and 3.

3 0
3 years ago
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