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Romashka-Z-Leto [24]
3 years ago
10

A fair coin tossed 3 times in a row. What is the probability that heads appear on only the last toss?

Mathematics
2 answers:
Monica [59]3 years ago
8 0

Answer: Probability that heads appear on only the last toss is \dfrac{1}{2}

Step-by-step explanation:

Since we have given that

A coin is tossed 3 times in a row.

Total number of outcomes = 8

Number of possible outcomes would be

{HHH,HTH,HHT,TTH,THT,HTH,TTT,HTT}

We need a probability that heads appear on only the last toss.

So, Number of possible outcomes becomes 4

i.e. {HHH,HTH, THH,TTH}

So, our required probability would be

\dfrac{4}{8}=\dfrac{1}{2}

Hence, probability that heads appear on only the last toss is \dfrac{1}{2}

Nadya [2.5K]3 years ago
5 0
The total number of ways you can toss a coin 3 times  is 8.
H H H
H H T
H T H
H T T
T H H
T H T
T T H
T T T
That should be 8 times.
H H T is the only toss that works
1/8 times
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The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.

Step-by-step explanation:

Let,

Price of one vegetarian special lunch = x

Price of one chicken special lunch = y

According to given statement;

21x+40y=467      Eqn 1

28x+36y=484     Eqn 2

Multiplying Eqn 1 by 28

28(21x+40y=467)\\588x+1120y=13076\ \ \ Eqn\ 3

Multiplying Eqn 2 by 21

21(28x+36y=484)\\588x+756y=10164\ \ \ Eqn\ 4

Subtracting Eqn 4 from Eqn 3

(588x+1120y)-(588x+756y)=13076-10164\\588x+1120y-588x-756y=2912\\364y=2912

Dividing both sides by 364

\frac{364y}{364}=\frac{2912}{364}\\y=8

Putting y=8 in Eqn 1

21x+40(8)=467\\21x+320=467\\21x=467-320\\21x=147

Dividing both sides by 21

\frac{21x}{21}=\frac{147}{21}\\x=7

The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/10081622
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#LearnwithBrainly

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3 years ago
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Answer:

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 77.8, \sigma = 8.5

Find the minimum score required for an A grade.

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Z = \frac{X - \mu}{\sigma}

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X = 87.8

Rounding to the nearest whole number

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Answer:

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Step-by-step explanation:

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