Answer C is the right answer.
Step-by-step explanation:
h(x) = f(x) * g(x)
h(x) = (2*3^x ) * ( 3*3^2x )
2 * 3 is easy, that will be 6.
The ground number 3 remains 3 in h(x), so that is easy too...
But with multiplying exponents, you can add them.
Let's concentrate only on the exponents of f(x) and g(x)... and add them...
x + 2x =3x
So, now combine the easy part with this new exponent, and you get <u>h(x)</u><u> </u><u>=</u><u> </u><u>6</u><u>*</u><u>(3)^(3x)</u>
<u>So</u><u> </u><u>answer C is the right answer.</u>
Answer:
D. ![\sqrt[3]{5^7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E7%7D)
Step-by-step explanation:
The formula for this conversion is:
![a^\frac{x}{n}=\sqrt[n]{a^x}](https://tex.z-dn.net/?f=a%5E%5Cfrac%7Bx%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Ba%5Ex%7D)
Substitute the values you currently have.
![5^\frac{7}{3}=\sqrt[n]{a^x}](https://tex.z-dn.net/?f=5%5E%5Cfrac%7B7%7D%7B3%7D%3D%5Csqrt%5Bn%5D%7Ba%5Ex%7D)
Since we know that
a = 5
x = 7
n = 3
Fill the square root with this.
![5^\frac{7}{3}=\sqrt[3]{5^7}](https://tex.z-dn.net/?f=5%5E%5Cfrac%7B7%7D%7B3%7D%3D%5Csqrt%5B3%5D%7B5%5E7%7D)
The regular hexagon has both reflection symmetry and rotation symmetry.
Reflection symmetry is present when a figure has one or more lines of symmetry. A regular hexagon has 6 lines of symmetry. It has a 6-fold rotation axis.
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Rotation symmetry is present when a figure can be rotated (less than 360°) and still look the same as before it was rotated. The center of rotation is a point a figure is rotated around such that the rotation symmetry holds. A regular hexagon can be rotated 6 times at an angle of 60°
http://prntscr.com/96oxjx
Answer: 
Step-by-step explanation:
Given
Azmyne decided to study a total of 
She spent 
on Friday and 
on Saturday
Hours spent on Friday
Hours spent on Saturday
She must study for
