Well if u multiply 305feet by 1/100 in your calculator you'll get 3.05ft tall
Answer:
(a) The future value after 9 years is $7142.49.
(b) The effective rate is 
.
(c) The time to reach $13,000 is 21.88 years.
Step-by-step explanation:
The definition of Continuous Compounding is
If a deposit of 
dollars is invested at a rate of interest 
compounded continuously for 
years, the compound amount is
(a) From the information given
Applying the above formula we get that
The future value after 9 years is $7142.49.
(b) The effective rate is given by
Therefore,
(c) To find the time to reach $13,000, we must solve the equation
<u><em>Answer:</em></u>
1)
f(x)→ ∞ when x→∞ or x→ -∞.
2)
when x→ ∞ then f(x)→ -∞
and when x→ -∞ then f(x)→ ∞
<u><em>Step-by-step explanation:</em></u>
<em>" The </em><em>end behavior</em><em> of a polynomial function is the behavior of the graph of as approaches positive infinity or negative infinity. The degree and the leading coefficient of a polynomial function determine the end behavior of the graph "</em>
1)
a 14th degree polynomial with a positive leading coefficient.
Let f(x) be the polynomial function.
Since the degree is an even number and also the leading coefficient is positive so when we put negative or positive infinity to the function i.e. we put x→∞ or x→ -∞ ; it will always lead the function to positive infinity
i.e. f(x)→ ∞ when x→∞ or x→ -∞.
2)
a 9th degree polynomial with a negative leading coefficient.
As the degree of the polynomial is odd and also the leading coefficient is negative.
Hence when x→ ∞ then f(x)→ -∞ since the odd power of x will take it to positive infinity but the negative sign of the leading coefficient will take it to negative infinity.
When x→ -∞ then f(x)→ ∞; since the odd power of x will take it to negative infinity but the negative sign of the leading coefficient will take it to positive infinity.
Hence, when x→ ∞ then f(x)→ -∞
and when x→ -∞ then f(x)→ ∞
