1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rama09 [41]
3 years ago
5

1/2 w +2;w=1/9 Help

Mathematics
1 answer:
diamong [38]3 years ago
5 0

Answer:

2 1/18

Step-by-step explanation:

ok substitute w with 1/9

so the equation is now

1/2*1/9+2

Do multiplication first so,

1/2*1/9= 1/18

Now the equation should be

1/18+2

Finish it off by adding

1/18+2= 2 1/18

You might be interested in
Basic functions sample work! Help please
frosja888 [35]

Answer:

  See the attachment.

Step-by-step explanation:

Function notation: This means the description of the curve is written in the form ...

  f(x) = <an expression that describes the curve in terms of independent variable x>

The name of the function does not have to be "f", though f, g, h are traditional for generic functions. In specific cases, the function name might be related to the value the function delivers: <em>cost(n)</em> might be the function that tells you the cost of producing n items, for example.

The functions shown (square root, reciprocal) should be shapes you have memorized. You can check the scale factor at specific values you know, for example, √4 = 2, or 1/1 = 1. Hence both functions have a scale factor of 1 (no scaling).

___

The domain is the horizontal region where the function is defined. Square root is not defined for negative numbers; reciprocal is not defined for 0. Hence the descriptions of the respective domains must exclude these values.

___

The range is the vertical extent of the values each function produces. The domain and range are the same for both functions shown here.

___

Asymptotes are lines the function approaches but does not reach. The square root function has no such lines. (It reaches vertical at x=0.)

The reciprocal function has a vertical asymptote as x=0 (the value of x that makes the function denominator zero). And, it has a horizontal asymptote at y=0, a value that can be approached, but not reached, as x gets large in either the positive or negative directions.

___

End behavior: The square root function heads off toward (∞, ∞). The reciprocal function heads toward the value defined by the horizontal asymptote: y=0 as x gets large in magnitude.

3 0
3 years ago
Lins father is paying for a $20 meal. He has a%15 off coupon for the meal. After the discount, a 7% sales tax is applied. What d
Bas_tet [7]

Answer:

he pays $18.19 hope this helps have a nice day please give me brainliest

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Is x greater than, less than, or equal to 73 degrees?
puteri [66]

Answer:grater than

Step-by-step explanation:

mark brainliest please

6 0
3 years ago
Akram is 20 year old and his sister shazia is 15
mash [69]

Answer:

1) akram : shazia

20-4 : 15-4

16 : 11

2) akram : shazia

20 + 5 : 15 + 5

25 : 20

5 : 4

3) ratios are not always constant

7 0
3 years ago
ASAP!!! Use the pythagorean theorem to prove that the point (√2/2, √2/2) lies on the unit circle. I need setup, explination, ans
docker41 [41]

Answer:

In brief, apply the pythagorean theorem to show that the distance between the point (\sqrt{2}/2,\sqrt{2}/2) and the origin is 1.

Step-by-step explanation:

The pythagorean theorem can give the distance between two points on a plane if their coordinates are known.

A point is on a circle if its distance from the center of the circle is the same as the radius of the circle.

On a cartesian plane, the unit circle is a circle  

  • centered at the origin (0,0)
  • with radius 1.

Therefore, to show that the point (\sqrt{2}/2,\sqrt{2}/2) is on the unit circle, show that the distance between (\sqrt{2}/2,\sqrt{2}/2) and (0,0) equals to 1.

What's the distance between (\sqrt{2}/2,\sqrt{2}/2) and (0,0)?

\displaystyle \sqrt{\left(\frac{\sqrt{2}}{2}-0}\right)^{2} + \left(\frac{\sqrt{2}}{2}-0\right)^{2}} = \sqrt{\frac{1}{2} + \frac{1}{2}}= \sqrt{1}= 1.

By the pythagorean theorem, the distance between (\sqrt{2}/2,\sqrt{2}/2) and the center of the unit circle, (0,0), is the same as the radius of the unit circle, 1. As a result, the point (\sqrt{2}/2,\sqrt{2}/2) is on the unit circle.

3 0
3 years ago
Other questions:
  • Between x = 2 and x = 3, which function has a greater average rate of change than y = 13 -x ?
    5·1 answer
  • Ill records the wins and losses for his high school basketball team each year. He notices that the ratio of wins to losses has b
    13·2 answers
  • A plane is flying at 20,000 feet and the pilot wishes to take the plane 35000 feet. The angle of elevation that should be used i
    15·1 answer
  • Need help I will offer brainalist + 10 points for correct answer (:
    12·2 answers
  • A can in the shape of a cylinder has a diameter of 10 centimeters and a height of 6 centimeters. Which measurement is closest to
    7·1 answer
  • SOMEONE PLEASE HELP ME WITH THIS !!!!!!
    13·1 answer
  • What will be the value of his account in 5 years if he does not make any additional deposits or withdrawals?​
    9·1 answer
  • If a = -2 and b = -4 -3i, then find the value of a b in fully simplified form.​
    12·2 answers
  • PLEASE PLEASE PLEASE HELP ME I’LL MARK BRAINLIEST IF YOU DO
    11·2 answers
  • Find the reference angle for a rotation of 347º.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!