You could add them on a number line or count on your fingers.
Step-by-step explanation:
Left hand side:
4 [sin⁶ θ + cos⁶ θ]
Rearrange:
4 [(sin² θ)³ + (cos² θ)³]
Factor the sum of cubes:
4 [(sin² θ + cos² θ) (sin⁴ θ − sin² θ cos² θ + cos⁴ θ)]
Pythagorean identity:
4 [sin⁴ θ − sin² θ cos² θ + cos⁴ θ]
Complete the square:
4 [sin⁴ θ + 2 sin² θ cos² θ + cos⁴ θ − 3 sin² θ cos² θ]
4 [(sin² θ + cos² θ)² − 3 sin² θ cos² θ]
Pythagorean identity:
4 [1 − 3 sin² θ cos² θ]
Rearrange:
4 − 12 sin² θ cos² θ
4 − 3 (2 sin θ cos θ)²
Double angle formula:
4 − 3 (sin (2θ))²
4 − 3 sin² (2θ)
Finally, apply Pythagorean identity and simplify:
4 − 3 (1 − cos² (2θ))
4 − 3 + 3 cos² (2θ)
1 + 3 cos² (2θ)
Answer:
Distance of foot of ladder from building: <em>37.2 inches
</em>
Distance of top of ladder from building's base: <em>114 inches
</em>
Step-by-step explanation:
Please refer to the figure attached in the answer area.
A right angled triangle
is formed by the ladder with the building where hypotenuse is the length of ladder.
Hypotenuse, <em>AC </em>= <em>10 foot
</em>
Also, we are given that angle made by the base of ladder with the ground is
.
We have to find <em>AB</em> and <em>BC</em>.

Using trigonometric functions:


Distance of foot of ladder from building: <em>37.2 inches
</em>
Distance of top of ladder from building's base: <em>114 inches
</em>
Answer:
its 3
Step-by-step explanation: