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2 years ago

Help please answer in the order of colors i will mark brainliest

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

4 0

Answer:

Try this site Bellow

Step-by-step explanation:

M A T H W A Y

no spaces and it's all one word

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Mario is constructing a wall around a rectangular area which will cover a maximum of 60 square feet. The length of the wall will

Feliz [49]

Answer:

$W \le 6$

Step-by-step explanation:

Given

$Area = 60ft^2\ (max)$

$Length = 10ft$

Required

Represent the width as an inequality

First, we represent the area as an inequality.

$Area = 60ft^2\ (max)$

max as used above means less than or equal to.

So, we have:

$Area \le 60$

The area of a rectangle is:

$Area = L * W$

So, we have:

$L * W \le 60$

Substitute 10 for L

$10 * W \le 60$

Divide both sides by 10

$\frac{10 * W}{10} \le \frac{60}{10}$

$W \le \frac{60}{10}$

$W \le 6$

7 0

3 years ago

The Zamboni can resurface 1200 square feet per minute. How many minutes will it take the Zamboni to resurface the entire rink if

Alekssandra [29.7K]

Answer:

Step-by-step explanation:

sorry if wrong

7 0

3 years ago

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

2 years ago

Find the slant height l of the cone given the surface area S.

Oduvanchick [21]

9514 1404 393

Answer:

15 cm

Step-by-step explanation:

The formula for the surface area of the cone is ...

A = πr² +πrL = πr(r +L)

The radius of this cone is half its diameter so is (12 cm)/2 = 6 cm. Then the slant height L can be found from ...

126π cm² = π(6 cm)(6 cm +L)

21 cm = 6 cm +L . . . . . . . . . . . . . . divide by 6π cm

15 cm = L . . . . . . . . . . . . . . . . subtract 6 cm

The slant height is 15 centimeters.

6 0

2 years ago

An investment firm invested in two companies last year. They invested $40,000 in company A and made a profit of 15%. They invest

alexira [117]

Answer:

A) $8200.

B) 16.4%

Step-by-step explanation:

Here is the complete question: An investment firm invested in two companies last year. They invested $40,000 in company A and made a profit of 15%. They invested $10,000 in company B and made a profit of 22%.

A) What is the investment firms total profit?

B) What is the percent profit of the total investment?

Given: Company A invested $40000 and made profit of 15%

Company B invested $10000 and made profit of 22%

A) First lets find the profit of company A and B.

Company A= $\frac{15}{100} \times \$ 40000= \$ 6000.$

∴ Profit of company A is $6000.

Company B= $\frac{22}{100} \times \$ 10000= \$ 2200$

∴ Profit of company B is $2200.

Total profit= profit of company A+ profit of company B

⇒ $Total\ profit= \$ 6000+\$ 2200$

∴ Total Profit= $\$ 8200$

Hence, the total profit of investment firm is $8200.

B) Now finding the percentage of total profit made by firm.

Total investment by the firm= $\$ 40000+\$ 10000= \$ 50000$

∴ Total investment done by the firm is $50000.

Percent of profit= $\frac{Total\ profit}{Total\ investment} \times 100$

⇒ Percent of profit= $\frac{8200}{50000} \times 100$

⇒ Percent of profit= $\frac{82}{5} = 16.4\%$

Hence, 16.4% is the percent profit of the total investment.

7 0

2 years ago